 Hello and welcome to the session. My name is Mansi and I am going to help you with the following question. Now the question says, prove that the circle drawn with any side of a rhombus as diameter passes through the point of intersection of its diagonal. So let us see the solution to this question. We see that A, B, C, D is a rhombus. Then taking A, B as diameter, we draw a circle. First of all, we see that what is given to us. Here we have A, C and B, D are its two diagonals which bisect each other at right angles. Now what we have to prove that a circle drawn A, B as diameter will pass the point of intersection of its diagonals and we see here that the point of intersection of A, C and B, D is O. So the diameter will pass through O. First of all, let us do some kind of construction here that helps us solving this question. The construction would be we draw P, Q that means this F parallel to A, B parallel to A, D start with the proof to this question. Is a rhombus therefore A, B is equal to C, D. So first we have A, B is equal to D, C is equal to D, C so this implies half of A, B is equal to half of D, C. We see that half of A, B is equal to half of D, C. Now we know that C will be D, P. This happens because we see that this will be the center of the circle. So A, Q is equal to B, Q. So similarly Q becomes the midpoint of A, B equal to D, P because that you understood the question and enjoyed the session. Have a good day.