 Hi and welcome to the session. Let us discuss the following question. The question says ABC is the triangle right-angled at C. If P is the length of the perpendicular from C to AB and AB is equal to C, BC is equal to A and CA is equal to P, then show that PC is equal to AB. Now this is the figure of this question. We are given a triangle ABC which is right-angled at C. P is the length of the perpendicular. AB is equal to C, AC is equal to B and BC is equal to A. We have to show that P into C is equal to A into B. Let us now begin with the solution. We are given that triangle ABC is right-angled at C, AB is equal to C, BC is equal to A and CA is equal to B. We have to prove that into C is equal to A in here of a triangle given by half into base detuned. Now begin with the proof as base P others to B and BC is equal to A. So this is equal to BA. Let us name this as equation number one. Now taking P as base under ABC as AB into altitude that is to see equation number two. From one and two we get or we can say the solution by and take care.