 Hello friends, let's discuss the following question. It says, a hemispherical bowel is made of steel 0.25 centimeter thick. The inner radius of the bowel is 5 centimeter find the outer curved surface area of the bowel. So we have given a bowel which is made of steel and it is 0. 0.25 centimeter thick and we are given that the inner radius of the bowel is 5 centimeter and it is 0.25 centimeter thick and we have to find the outer curved surface area of the bowel and the formula for the curved surface area of the bowel is 0.25 centimeter thick and we have to find the outer curved surface area of the bowel. So this is the key idea. Let us now move on to the solution. We have to find the outer curved surface area of the bowel. For that we need to find the outer radius of the bowel, outer radius of the bowel equal to the inner radius plus the thickness of the bowel, right? This plus this that is 5 centimeter plus 0.25 centimeter, which is equal to 5.25 centimeter. Now we can find out the curved surface area of the bowel. In fact, we have to find the outer curved surface area. So this is equal to 2 pi r squared and here r is 5.25 centimeter. So this is equal to 2 into pi, pi is 22 upon 7 into r squared that is 5.25 centimeter square equal to 2 into 22 upon 7 into 5.25 into 5.25 centimeter square and this is equal to 1200 12.75 upon 7 centimeter square which is equal to 173.25 centimeter square. Hence the outer curved surface area of bowel is equal to 173.25 centimeter square. So that's all for the session goodbye and take care.