 Hello, and welcome to the session I am Deepika here. Let's discuss the question which says verified that the given function is a solution of the corresponding differential equation. xy is equal to log y plus c, y dash is equal to y square upon 1 minus xy, where xy is not equal to 1. So, let's start the solution. Now, our given differential equation is y dash is equal to y square upon 1 minus xy, where xy is not equal to 1. Let us give this equation as number 1 and the given function is xy is equal to log y plus c. Let us give this equation as number 2. Now, on differentiating both sides of equation 2 with respect to x, we get, now on the left hand side, we will apply the project rule. So, the left hand side is equal to x into derivative of y which is dy by dx plus y into derivative of x which is 1. And on the right hand side, we have, now derivative of log y is 1 over y into dy by dx or we can write this as x into y dash plus y is equal to 1 over y into y dash or we have y is equal to y dash into 1 over y minus x or y is equal to y dash into 1 minus xy over y, y dash is equal to y square over 1 minus xy, where xy is not equal to 1. Now, on substituting the value of y dash in the left hand side of the given differential equation or in the left hand side of equation 1, we have our left hand side is equal to y square over 1 minus xy, but this is our right hand side, hence our left hand side is equal to right hand side. Therefore, the given function is a solution of the given differential equation, hence we have verified that the given function is a solution of the given differential equation. So, this completes our session. I hope you have enjoyed the session. I will take you.