 Hi and welcome to our session. Let us discuss the following question. The question says, evaluate integral of sin inverse x divided by x squared with respect to x. Let us now begin with the solution. Let i is equal to integral of sin inverse x divided by x squared with respect to x. Differentiating both sides with respect to theta, we get dx by d theta equals to cos theta. This implies dx is equal to cos theta d theta. d theta divided by sin squared and cos theta into cos theta as second function. So integral is minus cos theta. Integral derivative of theta is 1. Integral of cos theta squared theta with respect to theta is minus cos theta minus theta cos theta integral of cos theta cos theta theta is log mod cos theta.