 Hi and welcome to our session. Let us discuss the following question. The question says that areas of two similar triangles are 81 centimeters square and 49 centimeters square respectively. If the altitude of the bigger triangle is 4.5 centimeters, find the corresponding altitude of the triangle. Let us first write down the given information. We are given that triangle A, B, C is similar to triangle D, E, F. N is perpendicular to B, C. And D, N is perpendicular to E, F equal to 4.5 centimeters equal to 81 centimeters square. An area of triangle D, E, F equal to 49 centimeters square. We have to find D, N. We have to triangle D, E, F therefore divided by area of triangle D equal to A, F square divided by D, N square because area of is of corresponding altitude is equal to 81 centimeters square. Area of triangle D, E, F is 49 centimeters square. Area is equal to 4.5 centimeters and we have to find D, N. Now this implies 9 by 7 is equal to 4.5 divided by D, N. And this implies D, N is equal to 7 into 4.5 divided by 9 and this is equal to 3.5 centimeters. Hence our required answer is 3.5 centimeters. So this completes the session. Bye and take care.