 Okay, so let's try this one more time. Okay, so listen to listen to what the words that are coming out of my mouth Okay, so if the temperature of a gas sample is increased from 20 degrees Celsius to 40 degrees Celsius What what do we already know about the gas sample guys? We know T1 and T2 right? What are they? 20 degrees Celsius is what? It's T1, right? Because why? It's that it increased from 20 to 40 degrees Celsius Everybody's like 293, right? What? Okay, what's T2 again? 40 degrees Celsius So it also says the volume was found to increase we'll say By seven well, we'll say two seven liters. Okay, the volume is found to increase to seven liters seven point Oh, we'll say okay, so What is that gonna be? Is that gonna be B1? B2, right? So seven point oh leaders, so we're looking for B1, right? We'll just say that's like that So now we can use Celsius in this problem, but normally you're gonna want to convert them to Kelvin Okay, so let's just get in the habit of converting everything to Kelvin. Okay, so how do we convert this to Kelvin? Add a 273 so 20 plus 273 is 293 Kelvin, okay, so this will be suitcase, okay Now we're using here 40 plus 273 is 313 Okay, so Let's use our ideal gas law PV MRT remember one one one one two P2 V2 and two are T2 Okay So bless you. What changed did P change? No, right, so what can we do to it? What can we do to it cancel it right? Did we change? Yes, so can we cancel it? No, no in change No What is the am again? The amount of gas or the number of moles usually It is the amount, but usually you'll see it in a number or does it ever change no and it's teaching Yes, okay, so our new law is V1 over V2 equals T1 over T2 So that is called Gay-Lusac's law, okay, and usually you'll see it written Oh well, this is Actually Charles so we're doing a Charles law problem again. Sorry about this, but let's just do another Charles law problem So again, like I said before you'll see it usually written V1 over T1 equals V2 over T2 Okay, but we can plug those in. This is a good one because we're now solving for the initial ball Okay, so what are we looking for? What variable do we want to isolate here guys? V1, okay, so How do we do that? It's an easy one to do, right? All we got to do is multiply both sides by V2, right? We've isolated V1 and it's on the top, right? That's all that matters. Okay, so V1 equals V1 V2 Over T2, right? And so now what do we do? Plug a chug, right? Same thing every time so T1 is 293 Kelvin 7.0 liters, those on your own, right? Cancel out your case, cancel out your Kelvin's, and what do you get, liters or a pool? Okay And so sent you going to do it to Six figs there. It's going to be actually 6.6 liters, right? And Last thing you want to ask yourself usually on these ones is does this make sense? Okay, so it says here the temperature went from Small smaller number to a bigger number, right? Would you expect that the volume went from a smaller to a bigger thing? Yeah, then is this smaller than 7.0? Is V1 smaller than 7.0? Yes, right? So that would be like if you want to think about it backwards if you put a balloon in the refrigerator, right? You would think it would shrink, right? Or if you put a balloon in a you know heated up a balloon like a hot-air balloon It's going to expand and that's what this is doing, right? You're heating up a balloon and it's expanding So you always want to take chemistry not just from in the classroom You know, but you want to take it from think about chemistry is all around it So you know what I'm saying and just think about what happens in the real world. Okay, we could kill Unless there