 Hello and welcome to the session. I am Deepika and I am going to help you to solve the following question. The question says, solve for x and y. x plus 6 over y is equal to 6. 3x minus 8 over y is equal to 5. So let's pass the solution. Now the given equations are x plus 6 over y is equal to 6 and 3x minus 8 over y is equal to 5. Now let us give this equation as number 1 and this equation as number 2. Now the given equations are not linear but can be reduced to linear form by making some suitable substitution. Let us substitute 1 over y is equal to p. So from equations 1 and 2 we have x plus 6p is equal to 6 and 3x minus 8p is equal to 5. Now we have expressed the equations as a pair of linear equations. Now we can use any method to solve these equations. Let us solve these equations by elimination method. Now again let us give this equation as number 3 and this equation as number 4. Now on multiplying equation 3 by 3 we get px plus 18p is equal to 18. Now subtract equation 4 from this equation to eliminate x because the coefficients of x are same. So on subtracting equation 4 from above equation we get minus 3x plus 18p plus 8p is equal to 18 minus 5. That is 26p is equal to 13 or p is equal to 13 over 26 which is again equal to 1 over 2. Now on substituting this value of p equation 3 we get now equation 3 is x plus 6p is equal to 6. So on substituting p is equal to 1 over 2 we have x plus 6 into 1 over 2 is equal to 6 that is x plus is equal to 6 or x is equal to 6 minus 3 which is again equal to 3. So we have x is equal to 3 and p is equal to 1 over 2 but we have assumed that p is equal to 1 over 5 so this implies 1 over 2 is equal to 1 over 5 and this implies y is equal to 2. Hence x is equal to 3 and y is equal to 2 is the required solution equal to 3 and y is equal to 2 is the answer of the above question. This completes our session. I hope the solution is great to you. Bye and have a nice day.