 the question is, find the set of values of 2. So basically your f-cache is, right? So what is my outcome for? Outcome, like the values. Why not? Because it's in the numerator. The discriminant e square minus 4, this should be given as minus 4y square plus 8y minus 4 is greater, which means minus 3y square plus y8 minus 2a plus a square minus 4 is greater than equal to 0. This is the quadratic equation whose coefficient of y square is negative, means it is a downward, correct? So the value, correct? Because it is on the x-axis as well, which makes this greater than and this is my, you realize like this. So only in this case, whatever value, it is not taking the passing. So question number 6, but anyways, you are not affected by, please, minus n times n plus 1 by 2x, correct? What about x? Yeah. Similarly, get an ideal of 2x as 2x minus fraction part of 2x. Similarly, jf of 3x as 3x minus fraction part of 2x and so on. Finally, we'll have nx together and n into n. Won't it become any x, which will get cancelled eventually with this. Question number 6, with max. Yeah, it's too much. This square f of x is finding complete set of values of a should be not out of 8. Now see here, this function is definite, it is 4 to 4. So if x go to 4, can safely say x square will belong to z, correct? Yeah. Now if mod is, if mod is becomes greater than 16, it will give you the jf as dangerous words. Oh, that's why you have to. So your answer is x would be greater than 16 or x would be less than b. Sir, but we only have 4 and if it becomes 16, it will become 1. Why? 1 is bigger even than b. Yeah. It's up to you. Option b. Option b. Please keep checking the answer. Parsi will make a correction. Question number 64. So far I have found things easy. Let's go to 64. Can I resist? Find the range of the function jf of 2 plus 9 where x belongs to the interval 0. Sign x. Everything becomes 0 and you will get me anything. Okay, that is one of the values in the range. But xc to 1, that's what I am trying to do. If you start considering sign of x, y, j and all, for any value between 0 to 5, it becomes 0. If you take xc to 1 case, when you take xc to 5, this becomes 1. That's what you do to 0. Yeah, that's what it's all about. You leave sign x and sign x by 2. Apart from that, xc becomes 1 in any given condition. What? This is 0. 0 or 0. This also? No, no, no. Sign x and sign x by 2 will leave it. Apart from that, after that you get sign x by 3, sign x by 4. It's so complicated. Only one of them is for the other set. These two values will be your range of the function. So your answer is 1 by 2 and n into or n square plus n plus 2 by 2. Is this an option? Yeah. D is the option. D is the option. So D is 65. Sir, can you set a soft point of the script and the cd paper? I have to cd paper. You'll set it. Can I discuss 65 or no? Yeah. Next is the product of all values of x satisfying the equation. Sign plus of cos of 2x square plus 10 mod x plus 4 by x square plus 5 mod x plus 3. 2 minus 18 mod x by 9 mod x plus 5 by 2. First of all, let this 5 by 2 cos inverse something. x square 5 mod x plus 3 minus 2 mod x. Which means x square minus 4 mod x plus 3 is equal to 0. Which means x is plus minus 1, x is plus minus 3. So the product... Sir, it's not x. It's not x. Sir, it's not x. So your answer will be minus 1 to minus 1 by root 2. That means two more solutions I'll get from. So altogether, three solutions option B is correct.