 Hi and welcome to the session. Let us discuss the following question. The question says, find the area of a rhombus whose site is 6 cm and whose altitude is 4 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal. Let's see its solution. Now first of all, we know that rhombus is a parallelogram equal to sites. So that means we can use the formula of the area of parallelogram to find out the area of rhombus. Parallelogram is base into height. Area of rhombus will also be equal to base into height. Now in question we are given that the site of rhombus is 6 cm. So here we can take this site as 6 cm, altitude is 4 cm. So altitude means height that is 4 cm. So let us substitute the values and find out the area of rhombus base that is 6 cm into height that is 4 cm. So this is equal to 24 cm square. Now we also know that area of rhombus is equal to 1 by 2 into D1 into D2 where D1 and D2 are the lengths of diagonals, the length of one diagonal that is 8 cm and we need to find the length of other diagonal. So let us suppose that D1 is equal to 8 cm and we need to find D2. Now let us substitute the values in the formula area of rhombus equal to 1 by 2 into D1 into D2. Now we already have the area of rhombus that is 24 cm square. So 24 equal to 1 by 2 into D1 into D2 that is 1 by 2 into 8 into D2 will get cancelled by the common factor 2 and we will get 24 equal to 4 D2. Dividing both the sites by 4 we will get 24 upon 4 equal to 4 D2 upon 4. So here 4 and 24 will get cancelled by the common factor 4 and here 4 and 4 will get cancelled. So we get 6 equal to D2. Therefore length of other diagonal is equal to 6 cm. Therefore the required answer for this question is first that is area of rhombus 24 cm square and second that is the length of the second diagonal that is 6 cm. With this we finished this session hope you must have enjoyed it. Goodbye and take care.