 Okay. So this one's on the practice exam and says proposed mechanisms to account for the following reaction. Please show the structures of the intermediates and using curved arrows indicate the electron flowing each step. So all of that subsequent information is just saying, this is how a mechanism works. So if you don't remember what that word means, that's what you're doing, okay? So showing the electron flowing each step, showing all transition states, all that stuff. Well anyways, I guess I just erased it, but it said HBR and diethyl ether, okay? So diethyl ether, in that case here, I'll rewrite it. HBR, diethyl ether. It is diethyl ether, that's just the solvent, okay? I didn't know I think it doesn't do anything in the reaction. It's just where the reactants are swimming around it. So if you're trying to react with that, you're going to get the problem. It's not the way it works, okay? So HBR, like I was telling Bridget earlier, you have to remember, strong acid, okay? Whenever you have a strong acid, that's going to react first. So you've got to find where the base is. If you have an acid and you only have one other reactant, then that other reactant is the base, okay? So this thing over here is the base. Now you've got to discover where your arrows on that base are going to come from, okay? You're either going to come from something with a long pair or a double bond, okay? Or a pi bond, okay? Do you have long pairs in this molecule here? That's a question for you all. Do you have long pairs? No. Do you have a pi bond in there? Yes. Yes, you do. Yes, that's a double bond, okay? So where are the electrons going to come from? The double bond. That's where it's going to be protonated. So if you don't know what a double bond is, pi bonds and stuff, you cannot be able to do mechanisms, okay? So there's an H here and an H here, so Markovnikov will add either way, okay? I'm just going to do it this way so we can show those are the two arrows, okay? So again, we've done this reaction many, many times, so hopefully by now you're getting pretty sick of this mechanism Okay, so we can get that carbocation down there. We got our minus there. Or we could have, how I'll just draw it again down here, product of that reaction, which would be that. And that would be our minus. Okay, if you go to this one, I didn't say the major product, we'll do all of the products, okay? This will be a minor product, okay? Now it's just going to attack the positive charge like that. And excluding stereochemistry, of course, excuse me, which I'm sure this problem is would have said includes stereochemistry because of course there's one stereoisomer with the forward and one with the back, but this one isn't indicated either. So there's going to be a number of pi stereoisomers. Okay, so that would be one product. Then you could get another product from just the bromine attacking manner. Okay, that would be a different product. Maybe in a similar proportion to that product. This product might actually even be more major than this one because of the stereocumbrance next door. So you've got a metal groove next to that bromine. But then there's going to be another product coming from this intermediate. And I'll just show that over here. So we're going to show that intermediate again. So we've got that positive charge there. Well, that's a secondary carotertiary, so you can do that. And the molecule will do that. So you've got a hydrogen there, right? You're going to do a 1, 2 hydride shift like that. A very carbocation like that. And of course we still have that Br minus hanging out, waiting to attack that thing. And I'll give you your third product. I'm too tall for this board. Okay, so product 1. And it doesn't say to identify every reader. It doesn't say anything, right? It just says do the mechanism. Okay, yeah. So, and if it said do the mechanism for any of the products, well, you could have done any of those questions on that. So it's again, it's just the same things when we've been going over and over and over. So if you're having trouble with this type of a problem, I would recommend that you just continue to work on mechanism, okay? Okay, thank you.