 Hello and welcome to the session. The question says, construct the triangle ABC in which BC is 8 cm, angle B is 45 degrees and the difference of side AB and AC is 3.5 cm. So, firstly let us interpret the given problem in the form of a rough figure. Then we will proceed with the construction. Now, according to construction 11.5 of your book, this case is the first case since here we have AB minus AC is equal to 3.5. This implies that AB is greater than AC. So, we will work according to the rule of case one. First we will draw, draw a ray, BX and we will mark a point C on it such that BC is equal to 8 cm. Now, we are given that angle B is equal to 45 degrees. So, we will draw angle YBC equal to 45 degrees with the help of a compass. Then we will mark a point D on it such that BD is equal to the difference of the given two sides that is 3.5 cm. Then we will join the point D with C and the next we will find the perpendicular bisector of the line DC that it intersects the ray BY at a point A. ABC is the required triangle. This is how we are going to proceed on with the construction. So, this is where the steps of construction and side by side we will construct our ray BX and then mark a point is equal to 8 cm. So, this is a ray BX and on this side we have marked a point C such that BC is equal to 8 cm. Now, in the second step we shall construct angle YBC is equal to 45 degrees with the help of a compass. The first we will draw 90 degrees angle and then we will bisect it to get 45 degrees angle. So, this is ray BY such that angle YBC is equal to 45 degrees. Third step we shall cut the ray BY point D is equal to the difference of two given sides that is AB minus AC. So, we will cut the ray BY at a distance of 3.5 cm from the point B point D on the ray BY such that VD is equal to 3.5 cm and the fourth step we have to join DC. So, we have joined DC. Now, let us move on to the next step and in this step we shall draw the perpendicular bisector, perpendicular bisector of line segment BC. It intersects the ray BY, it intersects the ray BY at a point A. Then to get the triangle we will join A to C which is our last step to construct the triangle, required triangle. So, in the last step we will join AC and hence triangle ABC is the required triangle. So, hope you have understood the construction. This is the triangle we have got by constructing it. So, hope you have enjoyed it. Take care and have a good day.