 Hello and welcome to the session. In this session we discussed the following question which says, in an election there were two candidates A and B. The total number of voters in this constituency were 50,000 and 60% of the total votes were polled. If 40% of the polled votes were cast in favour of A, how many votes were received by B? Let's move on to the solution now. In the question we are given that the total number of voters is equal to 50,000. Next we find out the total number of votes polled. This is equal to the 60% of the total votes. So this means this is equal to 60% of 50,000. This is equal to 60 upon 100 into 50,000. Now we solve this and this is equal to 30,000. So the total number of votes polled were 30,000. Next we find out the total number of votes received by A. This is equal to 40% of the polled votes. Now the polled votes are 30,000. So this is equal to 40% of 30,000 equal to 40 upon 100 into 30,000. Now on solving this we get this is equal to 12,000. So total number of votes received by A is equal to 12,000. Now let's find out the total number of votes received by candidate B. This would be equal to the total number of votes polled. That is 30,000 minus the total number of votes received by A which is 12,000. So this is equal to 18,000. So total number of votes received by B is 18,000. So 18,000 is our final answer. This completes the session. Hope you have understood the solution for this question.