 Hi and welcome to the session. I'm Kanika and I'm going to help you to solve the following question. The question says show that limit x approaches 0 log 1 plus x cube by sine cube x is equal to 1. Before solving this question, we should note two keywords. First one is limit x approaches 0 sine x by x is equal to 1 and second one is limit approaches 0 log 1. So we will solve this question. So this is the key idea in this question, the solution. We have to show limit x approaches 0 log 1 plus x cube left inside left inside is equal to limit x approaches 0. So of these two theorems, we have to multiply and divide this expression by and dividing this expression by x cube. We get