 So this combines with this, forms N into CO3, this is decarboxylation reaction and it forms C6H5C6H5C, this is again chromium beam. Now this is result of chlorine, we can take here bromine also, if we take bromine here you will get bromine. So these are the manner of preparation The last part is the reaction of the radiation, we have to memorize all this reaction. If there are 7 reactions we will write down in this department. So I will write it down. This is the first reaction we have when we have this CL and it is heated with NOH, then eventually you don't have to memorize it. Now the first product we get here is the CL combines forms and again this is one method of preparation of the next reaction we have in presence of what is salt, temperature around 200 to 200 degrees. So the product here will be chromium which is CS3 and it is used here. You must take care of one thing, this oxygen is not coming over here in this product. This hole is getting replaced, otherwise if this hole is, like this hole is this oxygen, then here the product should be what? OCS3, that is not negative, negative CS3 here. When this H is attached, you know here this hole comes from the solvent and this hole is not there, you have the extra oxygen, H2O. Another reaction you see when you use NH2 moles of NH3 with CO2, it is a method of preparation of NET, which is NH2. Other product which is not important, it is CO2, CO2 and NH2. But you must have to memorize these products. Anything you can also obtain from this, if you use NH2 or NH3, NHCl forms, ACl forms and NH2 attaches. Sinex we can also obtain, if you have CUCL at around 10 degrees Celsius, it forms CUCL and CN will attach to it, it is strong reducing agent. You will get benzene reaction plus Nc. If you use RCl, this R can be carried and this R if it is benzene, these two reactions, this is what you think, right? The name of the H2O is not there, this is not alkene. So, H2O reaction, both are H2O. First of all we have to realize the next factor which is also not there, because we have a company, you can understand. They have break, you will get later. So, this is our selection method. Now, in this history, the mechanism is important. Why it is important? I will tell you. Suppose, we have CH3-CN, positive charge in CH3, the entire acts as an electroparticle. So, this will attack on the benzene ring. So, next is there, what happens? The benzene ring, pi electron power, okay, this pi electron changes. See, I suppose this will arrive. What happens here? I will explain this as well. Yeah, I did. See, this thing is common of reaction of benzene ring. You see this thing in every system. Okay. So, what is the problem here? No, this thing is... Yeah. Pleasure. Pleasure. Pleasure. Pleasure. Pleasure. Pleasure. Pleasure. Pleasure. What is the problem? You have a secondary profile group attack. Oh, yeah. So, that would be the minor problem. The other one would be the major problem. Right? See, what happens as it's N plus, and this H plus, got it? So, this one is the major problem. Got it? So, I'll go out. No, no, no. The OH must get taken away. How does the reaction take place? See that? As it gives H plus, right? Now, this is electron...