 Hello and welcome to the session, the given question says the number log of a suitcase has four wheels each labelled with 10 digits that is from 0 to 9. The log opens with a sequence of four digits with no repeats. What is the probability of a person getting the right sequence to open the suitcase? So let's start with the solution. Now here the log opens with a sequence of four digits from 0 to 9 with no repeats. Therefore the total possible outcomes is equal to 10 C4 because from 0 to 9 there are 10 digits and four digits are required to open the log with no repeats. Therefore 10 C4 this is equal to factorial 610 upon 4 factorial into 10 minus 4 factorial and this is equal to 10 into 9 into 8 into 7 into 6 factorial upon in the denominator we have 4 into 3 into 2 into 1 which is the value of 4 factorial into 6 factorial that is n minus 4 is 6 and factorial. On cancelling these two and simplifying this we get 5040 as the number of possible outcomes. Now let us denote e by the possible outcome for a right sequence and this is only one. Therefore probability of the event e to get the right sequence to open the log is 1 upon the total number of possible outcomes that is 5040. Since probability of an event e is equal to the number of outcomes which are favourable to the event and the total possible number of outcomes. Thus our answer is the probability of a person getting the right sequence to open the suitcase as 1 upon 5040. So this completes the session. Bye and take care.