 Okay, last problem of the day, we'll do an easy one. So given the reaction equation here, suppose a student performs this reaction and obtains 0.875 grams of copper II carbonate, and the theoretical yield is 0.988 grams of copper II carbonate. What is the percent yield? Okay, so how do we do percentage? Mark over whole. Mark over whole times what? Times 100. Times 100. So in this case, the percent yield is going to be the what over the what? Actual over the theoretical times 100 percent. Very important, because the percent is your units, okay? So the actual yield, 0.875 grams of copper II carbonate divided by the theoretical 0.988 grams copper II carbonate times 100 percent. Cancel, cancel, 0.988, add to 0.36 figs, it's going to be 88.6. First, good job, guys. Remember, we have a test next time we meet, okay? Have a good one, guys.