 Hello and welcome to the session. I am Deepika here. Let's discuss the question, where in the following list of numbers forms an AP? If they form an AP, find the common difference D and write 3 more terms A, 2A, 3A, 4A and so on. Let's start the solution. Our given list of numbers is A, 2A, 3A, 4A and so on. We have A2-A1, this is equal to 2A-A which is equal to A, A3-A2 is equal to 3A-2A which is again equal to A and A4-A3 is equal to 4A-3A which is equal to A. That is, AK plus 1 minus AK is the same every time, that is it is constants. Therefore, the given list of numbers forms an AP with common difference D is equal to A. Now the next three terms are 4A plus A which is equal to 5A, 5A plus A which is equal to 6A and 6A plus A because A's are common difference, this is equal to 7A. So the answer for this question is, yes, the given list of numbers forms an AP with common difference D is equal to A and the next three terms are 5A, 6A and 7A. I hope the question is clear to you. Bye and take care.