 Take a minute to read this example. We want two forms of a line for this one. First, we want the slope intercept form and also, we want the standard form. So we're going to find one of them first. We'll find the slope intercept form first and then using that, we'll get the standard form. But before slope intercept, before standard form, we want to find, oh, pardon me, we want to find the slope intercept form, sorry, point slope form. So point slope form is where we're going to start. We'll use point slope form to find slope intercept, and then we'll get standard form. So first, let's begin with the point slope form. So we'll need a slope while we're given slope. That's up top here, negative two-fifths, and we need a point. Well, that's point N, which is 10 negative 5. So let's substitute those values into the point slope form. Now we'll use some algebra. We'll use the distributive property to start to get this point slope form equation into standard form. So first thing, notice, we have y minus negative 5. That's equivalent to y plus 5, and then we have negative two-fifths times x and negative two-fifths times negative 10. So that gives us negative two-fifths x plus, since we're taking a negative times a negative, plus 10 times 2 is 20, 25ths. And now 25ths, that can simplify instead of 25ths. We could say plus 4, because 20, sorry, 5 goes into 24 times. Now to get it into true slope intercept form, we'll have to subtract 5 from both sides, and so we have y is equal to negative two-fifths x minus 1. And so now we've achieved part of our task. It says write an equation in slope intercept form. While we've done that, there's our slope intercept form. However, we also need to find standard form. So now let's do that next, standard form. So standard form means the x's and y's are together on one side of the equation. So that means we'll have to add two-fifths x to both sides of this equation. Then lastly, all of the numbers must be integers. So since we have two-fifths x, we're going to multiply both sides of the equation by 5. We're going to multiply both sides of the equation by the denominator of the fraction. Then distribute that 5 in. 5 times two-fifths x is 2x. 5 times y, of course, is 5y, and then negative 1 times 5, let's just negative 5. And so there we have the standard form of our equation. And so now we've done both parts of the problem. Still a intercept form in the green and standard form in the blue.