 Hi, and welcome to the session. Let's discuss the following question. It says A D and B C are equal perpendicular to a line segment AB. Show that C D bisects AB. So let us first understand the basic approach to solve it. We'll prove that triangle B O C is congruent to triangle A O D and to prove that they are congruent we'll be using ASA congruence criteria. So let us understand what is ASA congruence criteria. If we have two triangles ABC and DEF then by ASA congruence criteria if two angles and one included sides are equal then we say that triangle ABC is congruent to triangle DEF. So this approach becomes the idea. Now we are given AD is perpendicular to AB and BC is perpendicular to AB. Also BC is equal to AD and we have to prove that C D bisects AB that is BO is equal to AO. Let's now start the solution. Now our aim is to prove that triangle BOC is congruent to triangle A O D. So in triangle BOC and A O D we are given that BC is equal to AD angle C BO is equal to DAO angle C BO is equal to angle DAO because they are right angles and angle BCO is equal to angle ADO because they are alternate angles as ADA and BC are parallel so angle BCO is equal to angle ADO. They are alternate angles and BC is parallel to AD. So we have proved that two angles and one included side of the two triangles are equal. Therefore triangle BOC is congruent to triangle A O D. Hence BO is equal to AO by CPCT that is the corresponding parts of congruent triangles are congruent. Hence we have proved that C D bisects AB by proving that triangle BOC is congruent to triangle A O D by ASA criteria. Hence the result is proved. So this completes the question. Bye for now. Take care. Hope you enjoyed this session.