 Okay, cool. So let's do this problem in your book. It's 4.77, okay. And there's the equation. N2 gas plus H2 gas goes to ammonia gas and H3 gas. So the first thing you need to do for this equation, of course, is balancing. So you want to balance, well, in this order and then H, okay. So here, on this side, we've got two ends. And on this side, we've got one. So we've got to multiply that by two, okay. And then, now we say we've got six hydrogens on this side of the equation and only two over here. So we're going to have to multiply this by something to make it six. So three times two equals six. Okay, so that's how you balance that equation. Okay, the second part to this problem says how many moles of hydrogen would react with one mole of nitrogen? 1.00 moles N2. We just used the conversion factor that we know. Three moles of hydrogen to one mole of nitrogen. Of course, we want to put the three moles of hydrogen on the top and divide that by one mole of nitrogen. We get that directly from the chemical equation. There's a one to three ratio of these two things. Of course, moles of nitrogen then cancel out. And if we multiply across, we get 3.00 moles of hydrogen.