 Okay, in one minute we will start, in one minute only, still there are many students who have not joined yet. Yes. Okay, what if I ask you one question to all of you, let's say, let's say H plus concentration, if H plus concentration is 10 to the power minus 3, what is the pH for that solution? If H plus concentration is 10 to the power minus 3, what is the pH? Can anyone tell me? Okay, pH is 3. H plus concentration is 10 to the power minus 3 means pH is 3. If H plus concentration is 10 to the power minus 11, what is the nature of the solution? If H plus concentration is 10 to the power minus 11, what is the nature of solution? Very good, basic nature, very good. If H plus concentration is 1, what is the pH? H plus concentration is 1, what is the pH? H plus concentration is 1, what is the pH? Okay, answer is 0. Because if I told you 10 to the power minus 3, then you said pH is 3. When 10 to the power 0, pH is 0. 10 to the power 0 is nothing but 1. Understood, so pH is 0. Is it clear to all of you? Concentration of H plus is 1 means pH is 0. Okay, anything to the power 0 is 1. Yes, so pH is 1. Okay, if I say H plus concentration is 1, then pH is... H plus concentration is 1, then pH is... Same thing. pH is 0 only. I have asked the same question only. H plus concentration 1 is nothing but pH is 0. Okay, students, now we are starting today's quiz. Already, if anyone is facing any issue, please tell me. Already, topic is acid bases and salt. Mostly questions are based on the... Okay, I know everyone. Mostly questions are from the salt preparation. Okay, students, now I am starting. Already if anyone is facing any issue, please tell me. At sharp 8, 4, they will start. If anyone who wants to join in, they can join in. Okay, fine. So, we will start in 1 minute. So, students, already? Yes. So, first question is in front of you. A method used to make a copper to sulphate crystal is shown. Place dilute sulphuric acid in a beaker. Warm the acid. Add copper to oxide until it is in excess. Filter the mixture. Evaporate the filtrate until crystals start to form. Leave the filtrate to cool. What are the purpose of... What are the purpose of step 3 and 4? Think about the salt preparation. These all steps are followed in salt preparation. What could be the purpose of 3 and 4? Ensure all the acid has reacted. And corresponding to that, it is like to obtain solid copper to sulphate. Be option to ensure all the acids have reacted to remove excess copper to oxide. See option to speed up the reaction to obtain solid copper to sulphate. And fourth one is to speed up the reaction to remove excess copper to oxide. Think about the process, you will get the answer. Okay, students. So, we will see what is the answer. Okay, 21 has answered it right. Many of you have answered it wrong. It is very easy question. You just need to see that. How it is... Okay. So, you just need to see. A method is used to make the copper to sulphate. Okay, now you see. This is the preparation technique. You put the dilute sulphuric acid in a beaker. Here you have H2SO4. Then you warm the acid. Then you add the copper oxide. Then you add copper oxide. Your reaction will be copper oxide plus H2SO4. Gives... Copper oxide plus H2SO4 gives you... Copper sulphate plus water. Copper sulphate plus water. Now, you add excess so that all the copper... All the hydro... The acid, H2SO4 should react. No more H2SO4 should remain in the solution. That's why you add excess of copper oxide. When you add excess of copper oxide, you can imagine that if you add excess, some amount of copper oxide remain unreacted. Because all of H2SO4 has already reacted. So some amount of copper oxide is left in the container. So what you do in the next step, you filter it. You filter it to remove copper oxide. So when you filter it, when you filter it, you will get the clear solution of copper sulphate. You get clear solution of copper sulphate. So what is the method to ensure all the acid has reacted is the step reason of adding excess. Filter the mixture to remove the copper oxide. Answer is V. Any doubt? Okay, anyone has any doubt? Please ask. No doubt, sir? Could we move to next? Okay, please mute your mic. Okay, fine. We are moving to the next question. So next question is... First, we will see the leaderboard. Mahabal is the fastest. We will see the second question. Different substance will dilute hydrochloric acid. For which substance could any excess not be removed by filtration? Copper oxide, you have only 50 seconds left. Copper to oxide magnesium. For which substance could any excess not be removed? By filtration. Any excess? You have last 18 seconds left. 60 students have answered. What? We will see what is our leaderboard. Okay, 28 have answered right. But more than that, people have made it wrong. Okay students, it's very easy question. Again, easy question in front of you. Question is this. A salt... Okay, you can see my... Salt can be made. Okay, first if you take copper oxide. You know copper oxide is solid. So if you add in FCR, let's say you are adding in hydrochloric acid. If it is in excess, just now we discussed. If solid is in excess, you can, you should remove it with the help of filtration. There is no other option. If you add magnesium, magnesium plus FCR also give you magnesium chloride. No doubt. That is soluble, aqueous. But the point is if you take magnesium in excess, so you need to separate it with the filtration. Like you have HCl here. If you add magnesium here. So if you add, after sometime you will have a little magnesium left. That needs to be separated through the filtration. That needs to be separated through the filtration and then you will get magnesium chloride. So here also you can't do. But the third option, sodium hydroxide, it is nothing but it is aqueous. It is already in the liquid state and you are making it react with HCl. So both are aqueous. So no need to go for the separation. No need to go for the filtration. Both are liquid. They hydroxide again solid. So if there is a solid, you need to go with the filtration. Is it clear? Any doubt? Next question. You will see the leaderboard first. Okay. Now frishti RnR is leading it seems. Good frishti. Micronomy. Okay fine. You will see the next question. Okay read the question carefully. A salt is produced in each of the following reaction. Okay I want to tell you if you have two minutes to solve the question. Please read the question carefully. Two minutes you have. Don't hurry. P is the magnesium plus dilute hydrochloric acid. Q is zinc oxide dilute hydrochloric acid. R is sodium hydroxide dilute hydrochloric acid. S is copper carbonate dilute sulfuric acid. Write reaction for each of them. Don't hurry. You have time. Last one minute. Okay. I think you have seen all these types of reactions. You need to understand the process involved. Okay fine. Answer is C. Very good students. Most of you have answered it right only. Those who have made it wrong. Just I will take 30 seconds to explain this question. So question is very easy. One minute. Yes. Question is very easy. Salt produced in each of the following. Magnesium plus hydrochloric acid. Mg plus HCl gives MgCl2. Plus hydrogen. No water. Zinc oxide plus H2SO4. Zinc sulphate. Plus water. Sodium hydroxide NaOH. Plus HCl. NaCl. And the last is copper carbonate. Plus H2SO4. Copper sulphate. Plus copper sulphate plus CO2. Plus water. All gives water other than one reaction. Water is formed. Flammable gas. Yes there is a flammable gas. All salts formed are soluble in water. Yes all salts formed are soluble in water. So answer is 1 and 3. Okay. Water is not formed in first reaction. Hope you understood this. Any doubt? Any doubt? Okay fine. Moving to the next question. Yes. We will see leaderboard first. Okay. Seems Dutch is leading good Dutch. Fine. Continue. The answer is salt. That's why I have included questions for salt. Zinc sulphate is soluble salt and can be prepared by reacting excess zinc carbonate. With dilute sulphuric acid. Which piece of equipment would not be required in the preparation of zinc sulphate crystal? Which piece of equipment would not be required in preparation of zinc sulphate crystal? All these equipment are in front of you. You must you can imagine that what all things can be required. In this few reactions we have just now discussed about zinc sulphate. So you know nature of zinc sulphate also. Thank you students. So which type of thing is not required? And please don't be hurry. Don't think that question is very easy. There is some point in the question. That's why I have included. Think and then answer. Okay. So last 10 seconds. Now we will see how many of you have made mistake. Not required. Not be required. And answer is. Answer is we will see. Oh my God. 22 students have answered only. Fine. We will see this. What will happen in this? Okay. Don't worry. We will see how to answer this question. Okay. Fine. This is the question. I will use you. In the previous missions we discussed that zinc sulphate crystals are soluble. So you would have thought that filter and funnel would be the answer. But before that question I told you you always add the salt in excess. So what about the excess salt my dear students? If you add the excess salt definitely if you write the reaction. If you write the reaction zinc carbonate with H2SO4 will give you ZNSO4. No doubt this is soluble. No doubt. No doubt this is soluble. So you would have thought soluble thing is forming. No need of filter paper or no need of filter funnel. But I before that question I told you you always take salt in excess. So what about the excess thing you need to separate it. That's why D is not the answer. So most of you have answered D. That's why I put this question I thought you will definitely think like that. So D is not the answer. Evaporating dish is required because to remove water you may need evaporating dish. Okay. Fine. This is not the answer but it is required. Okay. So it is required means not our answer. But if you see condenser you don't need condenser. It is also about without crystallization method we cannot obtain crystal. Without crystallization method you cannot obtain crystal. Why? You can get the crystals. Yes you can but you don't need the condenser for that. What is the question? Prepare the zinc sulfide crystal. Why you need condenser? You can do crystallization without condenser when you go to lab. When you go to lab you will observe that there is no condenser. What you do? In the evaporating dish you take this thing into evaporating dish. Okay. And you start heating this. Once you start heating it. Once it become a concentrated you remove this evaporating dish. Once it start becoming evaporated concentrated. Once it start becoming concentrated means less amount of water is there. You remove it from the heating. And you let it to cool. You let it to cool. So you don't need condenser at all. Yes you need beaker for that. How you will carry out the reaction. So this is also not our answer. Sir what is required in excess? Copper, zinc, carbonate. In the last question I explained you. To have the reaction if there is a H2SO4 present. And you put some salt. Your focus is like every whole sulfuric acid should react. Whole sulfuric acid should react. You put it in excess. So once you put it in excess after sometime you will find that zinc, carbonate is left. This you need to filter. Once you filter it. Once you filter is the filterate. The filterate you put into evaporating dish. This filterate you put into evaporating dish. And once you put in but what if excess was not given. What if excess zinc, carbonate they have given. They have given excess zinc, carbonate. Yes so again. Then question can be asked or you have not given excess. But if it is given in excess there are high chances that means this is the only method. If they would have not given excess means it become a difficult for the examiner to give the marks. But they have given excess so there is no point understood. What if it is not given then you could have gone for the other option also that filter panel also. But if you ask me in practical if excess is also not given the best answer would be condenser only. Best answer is condenser. If they give you the single correct best answer is this even if there is no excess word. Is it clear? Is it clear to all of you? Fine. Hope you understood this question. Okay let us see who has done this question right and who is leading now. Okay seems fine. Good Karan. Next question. Please read question carefully. Which of the following methods are suitable for preparing both zinc sulphate and copper sulphate? Reacting metal oxide with form dilute sulphuric acid. Reacting metal with dilute aqueous sulphuric acid. Reacting the metal zinc carbonate with dilute aqueous sulphuric acid. Select the best option. Don't don't hurry because you have time. You have one more minute left with you. A and D are same. Okay fine. So A and 2, 1 and 2 only. Okay please consider third option as 1, 2 and 3. If you have not marked. If you have not marked consider 1, 2 and 3. You have already marked? You have already marked? Have you already marked? Okay fine no worries. No worries, no worries. No worries, don't worry, don't worry. Don't worry. You give your best. So which option is 1, 2 and 3? Okay. You answer whatever you want. Okay if you feel A and D both are okay. You know why I told you don't worry? Why I told you don't worry? Because answer is B only. So it doesn't matter whether you have answered A or D. That's why I told you don't worry. Okay my dear students. You have again, oh sorry. One minute I will show you. Okay I will first solve the question. Okay you want to see the leader board. See the leader board first. Okay fine. Karun is leading. Now I will show you the question. Why I told you don't worry? Because answer is B. Okay now try to understand. What is the question? It's suitable for preparing both salt. Answer is reacting metal oxide. They have asked you reacting the metal oxide with warm dilute sulfuric acid. Metal oxide with warm dilute sulfuric acid. Yes both will give you the metal mince, metal oxide mince, zinc oxide plus copper oxide. If you make it react with H2SO4. If you make it react with H2SO4. Yes they are right that you will get copper sulphate and you will get zinc sulphate. No doubt. Okay fine option one is right. But my dear students. Okay this is previous leader board. But my dear students this is not the correct. This is not correct. Because the metal with dilute sulfuric acid copper won't react. Copper with dilute H2SO4. No reaction. No reaction. Because copper comes below hydrogen. Copper comes below hydrogen in reactivity series. Or zinc with dilute acid. The zinc with dilute acid definitely you will get the zinc sulphate. But not with copper. So this is not our answer. Reacting the metal carbonate with dilute aqua sulfuric acid. Yes this will give you the sulphate. Hope you understood and you learnt something from this question. Yes. Okay. So that's why the graph is like this. All are parallel. Means all are at the same height. You can see the graph. Okay I have already removed I think. Fine. So we will move to the next question. Okay. Now. Ready for next one. Please read question. This is the graph. See. 18, 18, 15, 7. It looks good. Fine. Next question. One minute. Why it is again showing that. Okay. It seems like last time I did not show you that. Leader board. Okay. Pura is bleeding. Very good Pura. Moving to the next one. Already. Please read question carefully. How many different salts could be made from a supply of dilute sulphuric acid, dilute hydrochloric acid, copper, magnesium oxide and zinc carbonate. Okay. Thank you. Long question. Yes. That's why I gave you time. You have time. Don't hurry. Okay. Fine. We will see the result. So answer is B. Fine. We will see where you all went wrong. Student C. It is very easy question. We try to understand. So question is this. How many different salts could be made from the supply of dilute sulphuric acid. You know, I want to tell you one thing here. They have given dilute sulphuric acid. They have given dilute sulphuric acid. Okay. So I will write H2SO4 and you have HCl also and you have copper also and you have magnesium oxide also and you have zinc carbonate also. All these three things. Okay. So these two won't react. H2SO4 and HCl won't react. Okay. We will take one by one. If I take H2SO4 won't react. Copper won't react. Why it won't react? Because it is lower than the reactivity series and you have taken dilute H2SO4 won't react. Magnesium oxide will react. Zinc carbonate will react. Here you will get zinc sulphate and here you will get magnesium sulphate. Okay. Similarly, if you take HCl if you take HCl this won't react. H2SO4 won't react. Copper won't react. Magnesium oxide will react. This will react. You will get ZnCl2. You will get MgCl2. Four salt. Copper won't react with any of these because it is a metal and it is not amphoteric. It is just matter. Okay. These two won't react with each other because both are solid. Both are solid. Both won't react. So answer is MgSO4 ZnSO4 4 is the answer. Is it clear to all of you? Any doubt? Any doubt? No doubts? Okay. I want to change this question little bit. I want to remove this dilute sign and I want to put here concentrated. If I put it concentrated what would be the answer? Who can tell? I want to see. If I put concentrated FCl sulfuric acid what would be the answer? Because both are solid. Because they have given magnesium oxide and zinc carbonate. Both are solid. So solid won't react. Is it clear? Someone asked. Momita is it clear? Both are solid. How they will react? Yes. HCl is dilute. No. Solid won't react with each other. Solid won't react. Okay. So answer if it is a concentrated sulfuric acid answer is different. Tell me what which other product you are going to get? Write the other product which are going to get I want to see. Which other product you are going to get I want to see. No one. Those who have written 5, 6 tell me which other product will form. Fine. I'll tell you. If you don't know concentrated sulfuric acid very good Disha very good very good. There are many students who have given right answer. Concentrated sulfuric acid is oxidizing agent. Is oxidizing agent. Your copper metal copper metal will react with concentrated H2SO4. It won't react with dilute but here it is acting as oxidizing agent you get copper sulphate. You will get copper sulphate and SO2 gas will also form. So this will one of the product. In that case answer would be 5. If it was answer would have been 5. If it was concentrated H2SO4. Is it clear? I hope those who maintain their nodes they are writing in their nodes. It is not displacing hydrogen. Strays you can't see any hydrogen see. Here you will get water. There is no hydrogen gas. There is SO2 gas because of the oxidizing nature. Oxidizing nature or you call it as oxidizing agent. Understood? Please remember this point. That's why I added this question. Concentrated H2SO4 reacts with copper dilute. Okay because dilute is not having that much of power dilute has water in that so it won't act as a strong oxidizing agent because you have already added water. When it is a concentrated it is more H2SO4 less water. So it can behave and the dominating part is H2SO4 but once it diluted it is not having that much of power. Understood? Understood? Strays always remember that's why we don't touch concentrated H2SO4 but we can touch dilute H2SO4 because of this reason only. Because concentrated H2SO4 is more powerful oxidizing agent more powerful acid also. Is it clear? Strays no no concentrated HCl won't react. Won't react. Yes it will react with your skin it will burn it. You know it is corrosive. It is corrosive means which give the burning sensation. Okay any other doubt? Or dilute? Dilute won't react. Dilute won't react. Understood? Would you move to next question? Hope you are learning new things. Okay Yes concentrated HCl has more H plus. Yes Ananya that's why we don't touch concentrated HCl also or it is a strong acid. Concentrated HCl is strong acid. Dilute Dilute has less H plus. Dilute has less H plus. Why doesn't it react with copper? Because copper is below hydrogen. Okay try to understand HCl is not oxidizing agent. H2SO4 is oxidizing agent that is that is the nature of H2SO4. H2SO4 can act as oxidizing agent HCl can't but H2SO4 can act as oxidizing agent only when it is concentrated. Dilute H2SO4 behaves only as acid. Concentrated H2SO4 behaves as acid as well as oxidizing agent. Write it in your notes. Is it clear? Concentrated H2SO4 oxidizing agent and acid Dilute H2SO4 only acid. Concentrated HCl acid Dilute HCl acid. Am I clear? If you won't write yes I can't go ahead. Okay fine next question. Please write these things in your notes. If you want time I will give you time to write that. Please think about burette and pipette. You must have seen in the lab in your school. 50 more seconds. What is burette and pipette? Okay I will show it to you. Wait. Okay I thought you people know what is burette and pipette. But you must have seen in the lab. You must have seen pipette is something you suck from mouth and burette is something which you put in a stand. Which you put in a stand. Okay fine no problem 60 students have answered. Okay 58 only. Sorry 60 I am not answered. Okay answer is B. Okay my dear students you know burette and pipette I want to show you. Just give me one second. See if you see lab apparatus. Chemical lab or chemistry lab apparatus you would see. Okay one minute. Okay so I think you can see my screen. Okay students this photo will help you. Now this is the where is the pipette. This is the volumetric pipette. I hope that you can see my concern. This is the volumetric pipette. You suck the solution from this and add in the container. Okay where is the burette in this? Just a minute. Where is the burette? Yes next to this is burette. Next is this is burette. Okay so one is the burette and one is the pipette. Okay I will tell you. Is it clear burette and pipette? Is it clear what is this? Okay I will come to that. Okay now I am coming to the question. Wait wait we will see what is the answer. Don't worry if it is different I will change it. Okay very good. So answer is potassium chloride from... Okay now think. Which solution can... Which salt prepare using burette and pipette? So only those salt can be prepared. Only those salt can be prepared. Whose acid and base are liquid. Are aqueous. Whose acid and base are aqueous. They are not in solid form. Okay and then I will explain the use. Wait for one minute. Okay Surya I can't do anything. Yes yes one minute. Okay so answer for this is calcium nitrate from calcium carbonate and nitric acid. No nitric acid is aqueous but calcium carbonate is solid. This is not the answer. Yes next is copper to sulphate from copper. Copper to sulphate from copper hydroxide. This is solid. This is aqueous. Potassium chloride from potassium hydroxide KOH Aqueous. And hydrochloric acid aqueous. Zinc and dilute S2SO4. This is solid. This is not. So answer is C. Answer is C. Yes answer should be C. Okay those who have answered C I will change the answer we will go with the C. Okay I will change it. Okay students please tell me if you have any doubt. In burette and pipette both things in burette and pipette someone ask for what is the use. You know later I will tell you the titration. Titration what you have. Like in titration you put acid and base. You mix acid and base to make salt. So what you do you put burette here on the stand. Here you have a burette on stand. Let's say this is a stand. And you put burette. And here you put your beaker. And you put in this beaker. You have already put solution of HCL with the help of pipette. With the help of pipette. Pipette gives you exact measurement of volume. Whenever you want to take the exact measurement and which is small in amount. Small volume you take with the pipette. And burette what burette do. burette has a controller. Here you have a controller. So you can control the flow of liquid from this. Here you put let's say NaOH. You control the flow of NaOH you can put drop wise. You can put drop wise. Is it clear? So this is the purpose of burette and pipette. Okay answer is C. I will change the answer. Any doubt? Yes. Titration can be used for a solvent. Concentration. Okay. You know titration is nothing but acid base reactions. There are so many titration you will learn in class 11. There are so many titration. One is the acid base titration. You take beaker. You take FCL in that with the help of pipette. And you take this beaker down. You take this beaker in the burette. This is nothing but burette. And this burette work is put the drop wise base. Now why we use them? Because you want to control the amount of base you want to control the amount of base. So what happens? When you control it and when you open it you can add it in drop wise. When you can add in drop wise as soon as as you must have heard about indicators. Yes. You must have heard about indicators. So indicator changes its color and whole acid react with base. So when indicator changes color we tight this knob. We stop the flow of base. This is the work of burette that you can control the flow of base even in droplets. You want to add one drop then you can add it. If you want to add 3 ml you can add it. Okay. Okay. Answer is C for this question. Okay. Now we have to do little fast because yes now one minute and the answer shows is D. Okay. Fine. I will make it answer C. The question number is 7. Yes. One minute. I will make answer C. Don't worry. Question number 7 is answer is C. One minute. One, two, three, four, five, six, seven. Seven answer is C. I have changed the answer. Don't worry students. I have changed the answer. Those who have even write answer they will get full marks now. Okay. Moving to the next question. Just one minute. I am going back. Okay. Okay. Fine. So I am sharing my screen. Okay. Fine. So you can see my screen. I am skipping all the questions fast because we have already done these. Okay. Fine. So now I have changed the leader board. I have changed the question. Answer of that question. Okay. This is the answer now. Now I think those who have done it right they would get full marks. Okay. Next question. Are you all ready? All ready. Next question. Please do this. Copper carbonate reacts with dilute sulphuric acid to make copper sulphate. Which row gives the correct order of steps for making copper sulphate crystal? We have already done this type of question. Quickly answer it. I have changed the answer students. Don't worry. No. You need means you as someone has asked has asked one question. So is it possible to determine whether the salt is solid liquid or gas without experimentation? Yes. You can without experiment you can remember. You need to remember. Like BACL2 is soluble. BSO4 is insoluble. Okay. There are 15 questions. I don't think that we could finish all. We will try to finish whatever we can finish till 9. We will see. Okay. So this question I have already done in question number 1. If you remember question number 1 it is same like that. Okay. Still you have people made mistake in this. 16. Okay. Answer is C. We will see. We will see. Don't worry. Okay. So just a minute. Okay. Question is copper carbonate. Okay. Access copper carbonate. First thing I told you access copper carbonate. Evaporate. Okay. So if you remember what you have answered copper carbonate. Which rule gives the correct order of steps for making copper sulphate crystal. Add excess of copper carbonate. Yes. To the acid. Okay. Evaporate to point. Okay. What you are saying? It should be filtered first. Evaporate to dryness. Leave it to cool. You are saying answer should be. Okay. Add copper carbonate and filter. Add excess copper carbonate. Evaporate to a point of crystallization. Okay. You are saying that filter it first. Evaporate. Filter it to point of crystallization. Leave it to cool. So. Yes. Option D should be the answer. Okay. So. Answer is D. Evaporate filter it to point of crystallization. Okay. And leave it to cool. Yes. Okay. Don't worry. I will change it at the end of the end of this thing. I will change. Don't worry. Okay. Question number 8 answer I will change it to D. Next one. Okay. One minute. We are moving to the next question. Okay. Next question is. Okay. One minute. One minute. Yes. You may be right. I have not seen the formula compound. Just a minute student. Very good question. Copper sulphate is forming. Yes. Yes. Copper sulphate is forming. So what will happen? Very good. So it is soluble. All things are soluble. No need to filter. No need to filter. So evaporate to point of crystallization. Okay. So copper sulphate is forming. Yes. Yes. Yes. Yes. Yes. Yes. Okay. So copper carbonate with dilute sulphate which row gives the correct answer of structure of copper sulphate crystal. Okay. You are saying that add excess copper carbonate. Yes. But still you are adding excess copper carbonate. You need to filter. Yes. You need to filter evaporate filter of point of crystal evaporate filtrate to point of crystallization. Yes. Answer is D only. Don't worry. Don't worry. Answer is D. Okay. Next question is. Next is. Fine. Students we are moving to the next one. You don't have much time. So next is in front of you. Just read question carefully. Yes. Please answer this question. Salt, X and Y. Okay. I will come to that question. Don't worry. Salt, X and Y are separately dissolved in water. Sample of the solution obtained are separately tested with dilute sulphuric acid and with aqueous sodium hydroxide. In two of the test the gaseous product are formed. In two of the test a gaseous product is formed. No precipitate is formed in any of the test. What are the salt, X and Y? HCl you have added. And both time you are getting gaseous. In two of the test this question we have already done. In some in our last centre mark. Okay. I'll come to that question. Don't worry. Okay. So answer for this is C. Answer for this is C. Because ammonium chloride in NaOH gives you ammonia. Last centre mark I discussed. Ammonium salts with alkali gives ammonia. And copper carbonate with HCl gives CO2. So answer is C. This I told you in last centre mark if you remember. Okay. Aneros carbonate salts with HCl give CO2. They are not reacting with each other. Okay. Fine. I'll show the question. Question is this. They are not reacting with each other. They are saying that tested with this and this. You are adding NaOH and HCl. You are adding NaOH and HCl. So if you add HCl to Na2CO3 you will get CO2 gas. When you get and so can you explain the previous question on again in the end of the class. Definitely this I will explain. Okay. Yes. Yes. I will increase. Okay. Is it clear? Question number 9 is clear. I'll come to question number 8 again after finishing this. Question number 9 clear. Moving to the next question. We'll see how much we can finish. I'll come to question number 8 before the class and don't worry. Question number 9. Over now question number 10. Okay. We'll see leaderboard after this question. A liquid turns white and hydrous copper sulphate blue and has a boiling point of 103 degree Celsius which could be the identity of liquid. Only 40 seconds you have now. Okay. 18 seconds left. Okay. So answer for this question is. Answer for this question is nothing but thought solution. NaCl. NaCl is the answer. Why? Because NaCl you know that when you add some impurity in water. When you add impurity in water its boiling point increases. So it goes to 103 degree Celsius. And NaCl has a water which will convert your anhydrous copper sulphate into hydrous and that is blue in color. Understood? Any doubt? Any doubt students? Yes or no? Okay. Yes. 100 degree Celsius is pure water. Next question. Salt is also, salt solution is also having, always having more boiling point than water. Okay. Satyam is leading. Next question. Be ready it will have only, I think it's 60 seconds only. Please check. Okay. Okay. I think it's repeated. Yes. Salt can be prepared by reacting dilute acid. No. You can do it. Copper chloride you want to form. Okay. Fine. So, question number 11 is, yes no worries you go ahead you write the answer. Answer it past students. Okay. Fine. Answer for this question is, C is the answer. Yes. It's C is the answer because 1, 2 is not the correct because copper is there. Copper won't react with dilute acid. We have already discussed similar question. We have discussed similar question. Okay. Okay. Next question. We have already discussed that question similar question. Okay. Read this question carefully. If you have only 60 seconds to answer this. Okay. Okay. Students metallic oxides are bases. Non-metallic oxides are acid. So many times we have discussed this. Yes or no. Any doubt? Metallic oxides are bases. Non-metallic oxides are acids. Any doubt? No. Okay. Next question and I think it is the last question for today's class. Then I will discuss question number 8 because many of you have doubt in that. This is the last question of this class. Okay. You have only 60 seconds to answer. The salt which is in the solution give pale green precipitate with sodium hydroxide solution and a white precipitate with varium chloride solution. After this question I will change the question number 8 answer so you can see who is the winner for today's quiz. I think but we do not have much time. If you can wait I will continue. There are two more questions. Idiom chloride you are using. Okay. Students answer is sulphate. Iron 2 chloride is the answer. Okay. Most of you have answered it right. Iron salt is there and sulphate is forming. Iron chloride. Iron 2 chloride I told you. Barium sulphate is the precipitate. Yes. Any doubt? Okay. Fine. We will do one more question. There are two more questions are there but let's see. Okay. Fine. Do this. Fast. The example of complex salt is. Please answer it. Example of complex salt. It is having 1 minute 25 seconds but you can finish it off fast. Example of complex salt is complex salt. Okay. Please students answer it fast. Either you know or you don't know but you have to observe something in the names. If you observe something you will get the answer. What is complex salt? Okay. If you don't know so observe the options carefully. Observe option carefully. You are not expected to know the complex salt but you are expected to generalize the thing. Very easy. Answer is very easy. You will learn it later that what are the complex salt but if you see the naming. Complex salt cation is named in the last. Cation is not named in first. So answer is D. Complex salt cation is not in let's say sodium chloride. Sodium is cation. It is named in first. Yes. Cation is named in first. Student I am just for 1 minute I am sharing my screen. So cation is named in first. In case of sodium chloride. Understood. So just 1 minute. I will change the answer of question number 8. Now I have changed the answer of 8. So those who have any issue with that that will. Okay fine. Now I have changed and we will start with the last. The last question is left. I think we will start with that. Okay fine. So just 1 question student just 1 question. Sorry for this. Just 1 question we have. Okay. So I am showing my screen. Yes I will show you to the leader board. Okay. So next question is coming to you. Don't worry last question which is left. And I will explain the 8 one. Those who have still doubt in that I will explain it. Okay this is the last question. Yes. Now students are you all ready? This is the leader board reading. Okay. And the last question is in front of you. Okay. An acid which is not a hydra acid. Acid which is not a hydra acid. Very easy question. Acid which is not a hydra acid. Which is not a hydra acid. It is not a hydra. It is hydra. Hydra acid. Think think think. You are not supposed to know each and everything. But you can apply your concept. Word you can apply. Hydra acid. Hydra acid. Hydra acids are the acids which are having only hydrogen and halogen. So H2SO3 is the answer. H2SO3 was the answer. Otherwise all of them have the hydrogen and non-metal. Hydra acids are acids which have hydrogen and non-metal. So students I will show the last question. This is the last question. B is the answer. Understood? B is the answer for the hydra acid. Which has hydrogen and halogen. I am going to question number 8. But I will come to that. One I will show you the leader board. So those who want to leave they can leave. The board final result is this. After changing question number 8 answer. So I think the winner of this quiz is Satyam. Congratulations Satyam. Ok fine. Now Satyam those who have doubt. Anirudh has doubt in that. Anirudh question number 8 we have doubt. Now see it is very easy. Any doubt in question number 8 answer is D. Because there are chances that copper excess you have taken copper carbonate. You have taken excess copper carbonate. So add excess copper carbonate to acid then filter it. As I explained in the first part. Ok thank you students. Thank you bye. Ok question number 7 you have doubt. Ok fine. In question number 7. I will show question number 7. Which of the salt is burated? You need to think which all are aqueous. Which all are in liquid form. If both things are liquid then this will be your answer. Ok so calcium nitrate. Calcium carbonate is solid. This is liquid. Aqueous. Copper hydroxide solid. This is aqueous. But potassium hydroxide is aqueous. And hydrochloric acid is also aqueous. And zinc chloride is zinc is metal that is solid. And this is aqueous. Is it clear? The answer will be C. Is it clear to all of you? Yes or no Aditya? Ok 10th question. Hydro acids are the acids which have hydrogen and halogen. Hydrogen and halogen no oxygen. Hydro acid. Question number 10. 103 degree Celsius. Alkohol has 78 degree Celsius. Petrol also not the answer. Ok. So petrol is also having less boiling point. That is why it boils off very easily as you put in the open air. Salt solution has a boiling point greater than 100 degree Celsius. That is nothing but impurity in any liquid. Impurity in liquid increases boiling point. That is the answer. So and the salt solution is also green. Ok the salt solution is there means it will provide water. So copper sulphate when get water will become copper sulphate.5H2O. That is blue in colour. Understood? So petrol was not a hydro acid. Petrol was not a hydro acid. So what was that? Not a hydro acid. Yes. So not a hydro acid means H2SO3 because it has oxygen in that. Is it clear? It has oxygen so it is not the hydro acid. Question number 8. Yes C. Question number 8. Ok titration is a big process. I cannot explain it in class but you will learn it class 11. Now just remember titration is mixing two things to calculate volume or concentration. Just remember one thing. Titration is mixing of the two solutions to calculate the concentration of one unknown solution. Ok. Later you will understand in detail. It is no point if I explain you here and it is a long process to understand. So just as of now you can imagine. Understand that way of calculating concentration is H2S is acid. Yes. Exactly it is acid. It gives you H plus and H2 minus. Any other doubt? Yes. Acid without O in molecules are hydro acid. Yes. Yes. Arane. Arane. Sorry. So there was a question which dealt with iron sulphate and iron chloride. Could you throw it please? Iron sulphate and iron chloride. Ok. Iron sulphate and iron chloride was a description where it is. Iron sulphate and iron chloride. Now one minute I forgot where it is. Iron sulphate. Here. Here. Sorry. This one. Because we need white precipitate that is nothing but VASO4 with barium chloride. And palegrip precipitate means Fe plus 2. Sensor is nothing but Fe2SO4. Fe2 plus salts are green. I told you in last class. Understood Siddharth? Yes or no? All clear students? Could you finish this now? Ok. Thank you students. Bye. Bye. Thank you.