 Hello everyone, I am Rahul Patil, Assistant Professor, Department of Mechanical Engineering, Walchand Institute of Technology, Solapur. Today we will discuss about projection of pentagonal plane. At the end of this session, student will be able to draw the projection of pentagonal plane. Now consider the problem, a regular pentagon of 40 mm side has a side parallel to HP and 60 degree incline to the VP. Draw its projections when its surface is 30 degree incline to the HP. Now before solving the problem, read the problem carefully and write down the given data. Here a regular pentagon of 40 mm side is given, side is 40 mm has a side parallel to HP and 60 degree incline to the VP. Now remember that inclination with HP is given, you have to draw it in the VP and when inclination with the VP is given, you have to draw it in the HP. Now inclination to the VP is given, this case you have to consider inclination with VP, it is in HP and inclination with the HP it is in VP. Now read the problem and can you answer a simple question, true shape of a pentagon is drawn in front view or in top view. As per the given condition, true shape of the pentagon is appear in the top view. Now start the drawing problem, in first stage draw x y axis, name as a x and y. Then draw the true shape of the pentagon, before that mark VP HP, then draw true shape of a pentagon like this and name it as a A B C D and E. Now this is the first stage where pentagon is drawn in the top view. For drawing the front view project all the points, point number A to E above the x y line, for that draw the projections from point A and B, point C and E and point D. Now you will get 3 points A B C and D, because A and B will appear on a single projection, similar way point C and E on appear a single projection, it will lie on a single point that is point A B point C E. Now join these 3 points, you will get a line view in the front view. Here first stage is completed, where pentagon is drawn in the top view, projection from all the points are drawn such a way that you will get a straight line in front view. Now for second stage remember that if first stage is drawn in the HP or below the x y line, then second stage is must be drawn condition with the HP. Now for that inclination with the HP is given, so that first consider any point on same line, here this point considered as A and B. Now as per given condition draw a inclined line with same dimensions, here inclination is drawn with 30 degree mark. Now remember that A to D distance drawn in the front view for stage number first is same, it is drawn A to D distance with inclination of 30 degree in the front view. Remember that this distance must be same, we have to just give inclination to that straight view. Now for completion of the top view in second stage, similar way draw the projection from point A B C E and D. Now for in top view projection from point A and similar way projection from point A, it will intersect each other at that intersection point mark as a point A. Similar way A and B will appear on a single projection, so that draw the projection from point B, you will get second point as a point B. Similar way draw projection from point C and E on C and V E, similar projections you have to draw from point E and point C, so that you will get second intersections point point E and point C. Similar way draw the projection from point C D, here you will get fifth point as a point D. Now join this point you will get A B, P C, C D, E and A. This is the second stage where surface is inclined 30 degree to the HP, inclination with the HP is drawn into the VP. Now third case you have to consider with the VP case, if object is drawn in HP second case must or second stage it is drawn with the HP consideration and third case it is with the VP. For third case as per given conditions draw a inclination line with the 60 degree. Now this pentagon appear on this 60 degree mark such a way that A B line must be lie on this 60 degree mark. For that purpose first mark this A B line on this 60 degree mark and then complete the diagram A B C D and E. That is second stage whatever pentagon is appear you have to same pentagon you have to draw for the third stage on 60 degree mark. Now in third stage you have to complete front view again. Similar way draw the projections from each point that is projection from point A projection from point B up to this project a line because A and B is lie on this line so that you will get same A and B point here. Again draw the projection from point C and point D so that you will get the positions from point A B C E and D in the front view. Now draw projection from point C point D and point E. Mark it as A B C D and E. Now join these lines A to B B to C C to D D to E and A to E. You will get the third stage where problem is completed. Now as per given condition where surface is inclined 30 degree to the HP and side A B is inclined 60 degree to the VP. While drawing remember that mention this inclination 30 degree and 60 degree if inclination with the HP is given you have to draw in the VP and when inclination with the VP is given you have to draw in the HP. These are the references. Thank you.