 Hello and welcome to the session. In this session we discuss the following question which says given that g is the greatest integer function and f is the absolute value function, solve f o g of minus 5 upon 3 plus g o f of minus 2. Let's move on to the solution now. We are given that g is the greatest integer function. So, we define g which goes from r to r such that g x is equal to the greatest integer function x and this is the value for the greatest integer function g x is equal to n where this x is greater than equal to n and less than n plus 1. In the same way we define f which is the absolute value function, f goes from r to r such that f x is equal to modulus x and this is equal to x when x is greater than equal to 0 and minus x when x is less than 0. So, we have defined both the functions g x and f x. We need to find the value for f o g of minus 5 upon 3 plus g o f of minus 2. First we consider f o g of minus 5 upon 3 and this would be equal to f of g of minus 5 upon 3 and so this is equal to f of now g x is the greatest integer function. So, g of minus 5 upon 3 would be minus 2. Now, f is the absolute value function. So, f of minus 2 would be equal to modulus of minus 2 which is equal to 2. So, we get f o g of minus 5 upon 3 is equal to 2. Now, let us consider g o f of minus 2 this is equal to g of f of minus 2. Now, f is the absolute value function. So, this would be equal to g of modulus minus 2 and this modulus of minus 2 would be 2. So, this would be g of 2. Now, g is the greatest integer function. So, g of 2 would be equal to 2. Therefore, we get g o f of minus 2 is equal to 2. So, now, o g of minus 5 upon 3 plus g o f of minus 2 is equal to 2 plus 2 which is equal to 4. So, what is our final answer? This complete C session hope you have understood the solution of this question.