 So yesterday or on Tuesday we finished off with the acid-catalyzed formation of a hydrate. We're going to use the same substrate and make the same hydrate, but we're going to this time use KOH and excess H2O. So let's draw a cyclohexanone again, okay, and you guys know what the product is. You can see it there on your page. So let's just go through the mechanism of this and see how this is different. Remember, with the acid-catalyzed, the first step was the prognation, okay? But here we don't have an acid to donate of, I mean, this actually is an acid at this point in time, but we're not going to use it as an acid in this reaction, okay? This is actually a nucleophile, electrophile reaction is what you'll find, okay? So KOH, of course, potassium is the spectator Ion. We're just going to put the OH-, so those electrons are hard to see. A little bit, but you have that negative there, so we know how many there'll be. Yeah, so I mean, it's good for you guys to keep in mind that when there's a negative charge on the oxygen, you know there'll be those three sets, yeah. So I mean, it's good for you to write those electrons down on your piece of paper when you're in class, though, you know. Okay, so like we said, the OH-, of course, is, makes the solution basic, but in this case, it's being a nucleophile, okay? Remember that this has that resonance form, right? Where we can take these electrons and put them up there, indicating to us that that carbon has a lot of positive characteristic to it. Like that, right? So that's the, that resonance form. So let's go back with double bonded carbonyl, okay? So electrophile nucleophile is going to attack. Notice it also said excess water, so that's going to be important. Whenever it says excess, it means more than a one-to-one mole ratio, okay? So in this case, we have a one, we could think of, we have a one-to-something more than one mole of water, which was down there, of that mole ratio, okay? So when we do that reaction there, so that arrow is that, right? And what have we done? We've attached that oxygen to that carbon, too, right? You guys been studying the mechanisms? Okay, this one is easier, huh, to do than those other ones that we've been doing? Or we've been just learning one? Okay. And of course, that's not the final product. So what's going to happen is we're going to have a water molecule here. This alkoxide here is going to be protein water. That's regenerating, of course, the hydroxide. So here we've got, what, a nucleophile electrophile reaction, and here we've got an acid-base reaction, a hydrohydride, right, so this is the base category. Is there any more, any questions on that one? Who may not, any questions? No.