 Hello friends, welcome to the session. I am Valka and I will discuss triangles. Our given question is B is a point on the side Bc of a triangle ABC such that angle ABC is equal to angle BAC. We have to show that C a square equal to Cv into Cv. Here is the figure. Now let's start with the solution. We are given that A, B, C is a triangle with angle A, B, C equal to angle BAC. We have to show square equal to Cv into Cv. Now let's start with the proof. Triangle A, B, C triangle B, A, C. B, A, C and A, B, C. We have angle C equal to angle B, A, C. We can see from both the triangles A, B, C and D, A, C that C is the common angle. Therefore we can say that angle C equal to angle C because this is a common angle. We can say that by A criteria similarity the triangle A, B, C is similar to triangle B, A. Now we all know that if two triangles are similar then the ratio of the corresponding sides are equal. So this implies A, B upon V, A equal to V, C upon equal to AC upon V, C. This implies Cv upon equal to CA upon on cross multiplying we get therefore we can say that CA square equal to Cv into CD proof. Hope you understood this solution and enjoyed the session. Goodbye and take care.