 This question is testing you on your understanding of limits. Assumption as x tends to zero, that will be okay. This question itself uses standard limits. What are x? x by x. One. Third one. What do you mean? This is completed. This is happy. This is completed. So that's your answer. Law of difference. It is 12 in x. How do you please start working this out? Is this assumption continuous at x equal to 1? You guys, that's the whole thing. Yeah, x minus 1. When you come to 2, what do you say? You think this is continuous at 1 and 2, let's verify. I don't know. Let's say I want to find the limit at minus 1. Let's say I want to find the limit. See here. Correct. This function reminds me of signal function actually. Correct. Left to 1, it will give you minus 1. Correct. Now see. When I am left to 1, this level will become what? Minus 1. Minus 1. Here it will not be substituted. So 1 minus 1. 1 minus. This will be plus 1. This will become what? 2 into 3. So the answer is for the left hand. Let's find out. Again, this will become plus 1. And of course, many of you were absolutely correct when you said it was discontinuous at x equal to 1. Correct. What should be the values? You should have calculated the RHL only at x equal to 1. In the x equal to 2, it's 12. Now if you just take RHL and this here is not matching. No, you are wrong. But you should know. You should predict that which one of them should be correct. Correct. Can't answer that question. If this is your thing, you evaluate RHL. Minus 1. Minus 1. 3 into 4, matching with the value at 2. So it's discontinuous at 2. This function. Or what is the sign of this function? Some of you... Next question. It's a very... Minus 1. Correct. Number is 14. What is the space? Let's check this. You are partly correct. This is 0, but this cannot be... You said it was discontinuous. I thought it was discontinuous. It's even 20. Is my thing clear? How much I do that even if it is 1 plus 0? What is the next 1 into 9, 1 into X equal to 0? 4. That graph. 1. Understood? So, you take function whose oscillation is minus 1. It becomes discontinuous. Obviously, this is neglected. So, how do you solve this? Can we take LCM and do it? You can directly do it. For what? For what? No worries. A quick session on that. It is easy. Yes. How do you pronounce this? I lost my hand. I lost my hand. I said it becomes 2-way. Let's see here. Okay. Now see the... Now again it is... So... What is the answer? What is the answer? The answer is going to be 1. So, how do you... You are like... You can't do this. Not to be used in school. No, you can't. No, try this in school. Over.