 Okay, so this one is very similar to the last problem. It says give the full or complete electron configuration and condense the electron configuration of each of these atoms. So again, you just look at the periodic table. So you know, aluminum's got 13 electrons in it. So here on a table, the full electron configuration, 1s2, 2s2, 2p6, remember you're just counting, so s block first, and then s block again, then the p block, then 3s2, okay, and you're almost there. So then aluminum, it's last electron is in that first b orbital, 31, okay, so if you wanted to do the condensed electron configuration, you just cut off at the valence electron. So noble gas before that, remember it is neon, so neon 3s2, and so this is the full one next to aluminum, so about aluminum, so it holds actually 3 orbitals, right, so they can each hold 2 electrons. To count them, you could a couple more of these after we talk about the transition metals and things below that.