 So this says you think condensed electron configurations write the reactions for the formation of the Common ions of indium. Okay, so it's very similar to what we did before But indium actually has two common ions. Okay, so things that Are atoms that are in the P blog Oftentimes will lose all of their P electrons to form their first common ion and then what they'll do is lose their S electrons, okay, because remember we talked about the contraction of the D and F orbitals when they get filled Okay, so they're not no longer the most outermost Orbitals, okay, so let's write starting right the condensed electron configuration of the indium So indium is I am Right, so we look for it on the periodic table number 49 there Okay, so the condensed electron configuration you guys can tell me if you want or not grip time, yeah What's next 5s 2 that makes sense right next 4010 and then 5p One let's talk or let's figure out what the two common ions for indium should be right So remember what I said right when you have these P block elements that'll you know Have a full D orbital they will lose their P's first And then that'll be a semi stable ion in and of itself and then they can lose the S's next, okay, so What two ions would you expect indium to make how about that or would you expect it to make it any ions 3 plus? That's one of them Because why plus is you want to lose the electrons, right? But that's not the client. That's the second ion. What was it one plus? Yeah, plus one Right, why did you figure out one? Because what did we say? Yeah, it's gonna lose its what first P orbitals first and then stay there So draw that so that's stable, you know that those filled these are stable We've talked about copper. We've talked about silver. We've talked about gold and what's the electron configurations for this guy? Is it just k r? So tell me what is it? That's the electron configuration for the second line So you should be able to take this predict this predict this right there electron configurations Okay, and of course quantum numbers for each of those electrons if I want to You guys are awesome at quantum numbers now, right or you will be the next time I talk to you