 Hi and welcome to the session. Let's work out the following question. The question says a body falls 16 meters in first second of its motion 48 meters in the second and 80 meters in the third and so on. How long will it take to fall 4096 meters? So let us see the solution to this question First of all, we see that here we have an arithmetic progression of these distances. They are 16 48 80 and so on. So this is an AP Here A that is the first term is 16 common difference. That is D is equal to 48 minus 16 That is equal to 32 now Let the body fall 4096 meters in n seconds So we will have some of n terms is given by n by 2 in 2 2a plus n minus 1 into D this implies 4096 is equal to n by 2 in 2 2 into 16 plus n minus 1 into 32 this implies 4096 is equal to n by 2 in 2 32 plus 32 n minus 32 Which is equal to n by 2 into 32 n Which is equal to 16 n square So this implies that n squared is equal to 4096 divided by 16. That is equal to 256 since n square is 256. This implies that n is equal to 16 So this is our answer to this question. I hope that you understood the solution and enjoyed the session. Have a good day