 Hello friends and how are you all doing today? My name is Priyanka and the question says a bag contains eight red six white and four black balls a Ball is drawn at random from the back find the probability That's the drawn ball is red or white not black neither white nor black. So here Let us draw a die from to model the situation So in this bag, we have eight red balls six white balls and four black balls so the total number of balls In the bag are this four that is equal to 18 Balls right in the first part we are required to find out the probability That the drawn ball is red or white So the total number of events that are favorable are Eight there are eight red balls six white balls divided by the total number of balls That is that are equal to 14 upon 18 that is further equal to 7 upon 9 so this is a required answer for the first part Similarly, we will be finding out for the second part here. The probability should be that it is not black So if it is not black then that means It will be white or red, right? So probability of not being black is equal to probability of being a red or a white ball in that we have found out above as 7 upon 9 so this is the answer to the second part and Finally For the third part we need to find out the probability that it's neither white Nor black So if it is neither white nor black then that means the probability of finding out a red ball Will be the required answer there are in total eight red balls divided by 18 and hence the answer comes out to be 4 upon 9 right so this is the required answer to the last and final part this completes the fashion too Hope you understood the whole concept of this question well and take care