 Hello and how are you all? Let us discuss the following question. Let's say solve the inequality for real X. The expression that is the inequality given to us is X plus X by 2 plus X by 3 is less than 11. X plus X by 2 plus X by 3 is less than 11. We need to simplify this inequality first. So we will be multiplying each term on both sides by 6 that is the lc of 2 and 3. So we have 6 X plus 3 X plus 2 X is less than 66 again. We have been multiplying each term on both the sides by the lc of 2 and 3 that is 6. After simplification we have 11 X is less than 66. Dividing both the sides by 11 we have 11 X divided by 11 less than 66 divided by 11. After simplifying we have the value of X is less than 6. So for real X the solution set consists of all real numbers less than 6. So the answer is minus infinity to minus to 6 in an open interval. So this completes the question. I hope you enjoyed the session. Bye for now.