 Hi and welcome to the session. Let us discuss the following question. The question says in each of the exercises 7 to 12 find the equation of the parabola that satisfies the given conditions vertex 00 passing through phi 2 and symmetric with respect to y-axis. Before solving this question we should know that if vertex of parabola is at the origin and coordinates of focus out of the form 0 a then equation of parabola is of the form x square equals to 4 a y. This parabola lies on the positive side of y-axis and this parabola opens upwards. So keeping this in mind let us now begin with the solution. We are given that vertex is 00, parabola is passing through 0.52 and is symmetric with respect to y-axis. The required parabola is passing through 0.52, it is symmetric with respect to y-axis. Now the 0.52 lies in the first quadrant and it is given to us that the parabola is symmetric with respect to y-axis. So this implies that required parabola lies on the positive side y-axis. This implies focus lies on the positive side and this implies required equation is of the form equals to 4 a y. Now putting s5 and y as 2 in this equation we get 5 square equals to 4 into a into 2. This implies a is equal to 25 by 8. By substituting value of a in this equation we get x square equals to 4 into 25 by a into y. This implies x square is equal to 25 by 2 y. This implies 2 x square is equal to 25 y. Hence the required equation of parabola is 2 x square is equal to 25 y. This is a required answer. So this completes the session i and take care.