 Hi and welcome to the session. I am Deepika here. Let's discuss the question. Find d y by dx of the following function. Function is x y is equal to e raised to power x minus y. So let's start the solution. Our given function is x y is equal to e raised to power x minus y. Taking logarithm on both sides, both sides we have log x plus log y is equal to x minus y in log e. Now we know that log e is equal to 1. So this implies log x plus log y is equal to x minus y because log e is equal to 1. Now differentiate both sides with respect to x. We have 1 by x plus now derivative of log y is 1 by y into derivative of y with respect to x. That is d y by dx is equal to 1 minus derivative of y with respect to x. So combining the terms containing d y by dx we have d y by dx 1 by y plus 1 is equal to 1 minus 1 by x. So this implies d y by dx is equal to 1 minus 1 by x upon 1 by y plus 1. So this is equal to x minus 1 upon x into y over 1 plus y which is equal to y by x into x minus 1 over y plus 1. So this is our d y by dx. Hence we have solved our question and our answer is y into x minus 1 upon x into y plus 1. I hope the question is clear to you. Bye and have a nice day.