 So let us take couple of questions on this. Okay draw a square with 1 meter per second, 2 kg going big. I was just asking whether you also can guess it. Alright, you need to find out the velocity of center of mass for this situation. You have four particles in your system and they are moving like this. You have to find out the velocity of center of mass. Now the chapter will be much more simple. I mean they will not be. Don't need to substitute the value. Yeah. Yeah. X, V, C, M, Y. Should I do it? No. It is simple. Alright, so big success. M1, V1, X, M2, V2, 1. Very good. How much? Minus 3. Minus 3. Oh, oh, oh, oh. Four seconds. So this is 4 meter per second. Similarly, VCM, Y, V3, Y, minus 3, sine 30, sine 45. So this will be 4 meter per second. So you can get VCM. Okay. So that's it for the velocity of center of mass. Not such questions which we have solved for velocity of center of mass for the velocity of center of mass. Are you getting it? Okay. Leg off. Excision of force. Okay. So when we find excision of force, how it is? Alright. Stop coming now. So we have till now found out VCM. Let's take 3 or 4 bytes like this. M1, R, R1, V1, M2, V2, so on, divided by M1 plus. How to find out the ACM? How to find that equation? The VCM is given? E. Differentiate. And so on, divided by M1 plus. M1 plus M2, right there. Okay. So this will be equal to M2 and so on, divided by M1 plus M2, like this, into ACM. It's capital M. Mass of the entire system is capital M. Okay. So the end is summation of M2 and so on, divided by the total mass of the system. So summation of M2 and so on is what? M into ACM of center of mass. Now tell me, when you add up, is equal to mass into acceleration of center of mass. Okay. What does it mean? This implies constant. The center of mass location won't change. Even if it's constant and hence, some of all, VCM velocity is not 0. VCM was 0. Find out how much capital M will move. Okay. The delta x is this much. Now tell me.