 Hi, and welcome to our session. This is just the following question. The question says, three copular forces acting on a particle are in equilibrium. The angle between the first and second force be 120 between second and third is 90. Find the ratio between the magnitude of the forces. Now, let the three forces, p, q, and r, be acting on a particle at o along o, x, o, y, and o, z, respectively. Courses 120 and angle between second and third force is 90. All these angles, so on subtracting some of these two angles from 360, we will get the measure of this angle. 360 minus 210 is 150 degree. So y is equal to 120. Angle y, o, z is equal to 90. And angle zelemi's theorem is equal to q y is p y. So we have sine equals to q y. We have sine 150 equals to r equal to 120. Thus, we have sine 120. p y 1 is equal to q y equals to r 3 y. Equal to 1 is to 1 by 2 is to root 3 by 2 is equal to 2 is to 1 is to root 3. These are required.