 So since you have ignored the energy loss points of the pipe and these two points can be, since I can apply it at any two points I can say that constant throughout the pipe number those kind of names. Very good at me. Normal names. Okay. Press kinetic energy per unit volume. Similarly, you don't give it potential energy that it means that rho g h at that point is that. Fine. So this one new kind of energy is does some work. So you're telling us two pointers on problem solving. How many equations you have even if you add plus rho g h y is constant. So you are going to use only these two equations. Nothing else. So what you should do, you should not think on which equation to use. Oh, very complicated. You don't have any, you should know between which two points are applying these equations. All right. And most of the time you are just playing around with these two equations only. You don't need to worry. And the numericals will be straight forward. If you understand these few things with respect to problem solving, you're going to get in this topic. And why only couple of things I have talked about in problem solving is to talk about. And just these couple of things that you need to take care of. Okay. Now I just ask you a question. Tell me. The water flow is more or less than the pressure on the tank. You have to use only c comes out. Correct. So you should be knowing exactly which two points you're talking about. So just choosing to print to do. So let us take few numericals now. I'm interested in finding velocity V2. This I have shown the cross section like this. And then show it to me. Don't solve it right. So V2 plus 1 minus A2 minus the power minus half. But you cannot just A into per second. So don't get confused. Volumetric. That's what I said. Q is water saturation. It is a law. You can use it anyway. What's without? Dejan which has an edge in it. What is the point of your school textbook? When board paper is sent, nobody cares about who has taught you what. you want. In both examples, some extra person will send the paper, only this much. For a pipe of this thickness, this is the actual thickness of the pipe. If your pipe has this much thickness, something of this size only, the pipe can go on and on. So, inside the pipe itself, it encounters the venturi meter. So, your pipe is there. In between the pipe, there is a venturi meter. This procession area, procession area of both sides of the venturi meter will be same. And since you have related venturi meter, u and diameter of venturi meter. So, these things are known to you. Capital A is known to you and small a is a procession area of the neck. That is also known to you. It is a venturi meter. Stop talking. Stop talking. It is useful. But right now, you first stop talking. In terms of p1, p2, right? So, please find out what the value is. So, p1 plus stop talking. I will just pick something that someone will get. See, I can u and h to both are 0. So, rho g h will not appear itself. So, p1 plus half rho v1 square is equal to p2. Which should be more than, this is more than that and some of this and that is constant is, let's, if we are not getting h more than p2, since this is greater than that. So, we have seen that in velocity. So, pressure energy will decrease. Some of the next to the moving train is like pk. What? Some similar incidents? Something similar? What are you talking about? To p1, okay? So, if you get close to it, you don't get 0. Take minus 1. Be careful. How you, see here density is known. Capital A is known. Small a is known. But p1 and p2 and that is using, since p1 is more than p, from this side more. Yes or no? Okay. Now, you are using water in the pipe. So, you should better use a heavier fluid inside the manometer and that is mercury. Okay. So, let's say this is mercury density. All right. And let's say the height difference is bench because density is very less. So, similar kind of pressure. So, pressure over here. I can say it is p1 and pressure over here. The pressure here will be more. You forgot is that law itself. You are telling me minus. So, p1 minus, you have a scale over here. So, now I can substitute the values what I can measure. So, the answer to it is 0 and gh. So, 2 times minus 1. This is velocity. Fine. That is the water. So, flow rate is how much? This into? Which way? So, capital Q is this flow rate. This much volume of water is flowing per second in the pipe. The entire manometer.