 Hello and welcome to the session. Let us discuss the following question. Question says, a game consists of tossing a 1 rupee coin 3 times and noting its outcome each time. Hanif wins if all the tosses give the same result that is 3 heads or 3 tails and loses otherwise. Calculate the probability that Hanif will lose the game. Now first of all let us understand that probability of occurrence of an event A denoted by P e is equal to number of outcomes favourable to E upon total number of possible outcomes. Now this is the K idea to solve the given question. Let us now start with the solution. Let us consider an experiment in which a coin is tossed 3 times. The outcomes associated with this experiment are heads, heads, heads, head, head, tail, head, tail, head, tail, head, head, tail, tail, head, head, tail, tail, tail, head, tail, tail, tail. So clearly we can see total number of possible outcomes are 8. So we can write total number of possible outcomes is equal to 8. Now we are given in the question that Hanif wins if all the tosses give the same result that is he wins if he gets 3 heads or if he gets 3 tails. He loses the game if all the tosses do not give the same result. So for all these results he loses the game. So total number of outcomes favourable to lose the game is equal to 6. From K idea we know probability of occurrence of an event E is equal to number of outcomes favourable to E upon total number of possible outcomes. So probability that Hanif will lose the game is equal to total number of outcomes favourable to lose the game upon total number of possible outcomes. Now we know total number of outcomes favourable to lose the game is equal to 6 and total number of possible outcomes is equal to 8. So probability that Hanif will lose the game is equal to 6 upon 8. Now we will cancel common factor 2 from numerator and denominator both and we get 3 upon 4. So we get probability that Hanif will lose the game is equal to 3 upon 4. This is our required answer. This completes the session. Hope you understood the solution. Take care and keep smiling.