 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question says find the distance between the following pairs of points minus 3, 7, 2 and 2, 4 minus 1. Before starting with the solution let us see the key idea behind the question that is if a point P that is x1, y1, z1 and a point Q, x2, y2, z2 are two points then the distance between them that is PQ is given by square root of x2 minus x1 the whole square plus y2 minus y1 the whole square plus z2 minus z1 the whole square. So using this formula we find out the distance between the two given points. So let us start with the solution to this question. Let the point P be minus 3, 7, 2 and the point Q be 2, 4, minus 1 then PQ that is the distance between P and Q is given by square root of 2 minus minus 3 the whole square plus 4 minus 7 the whole square plus minus 1 minus 2 the whole square. Now 2 minus minus 3 is same as 2 plus 3 so it is equal to square root of 2 plus 3 the whole square plus 4 minus 7 is minus 3 so minus 3 square plus minus 1 minus 2 is again minus 3 so minus 3 the whole square. This is equal to square root of now 2 plus 3 is 5 and square of 5 is 25 square of minus 3 will be 9 again square of minus 3 will be 9. This is equal to square root of 25 plus 9 plus 9 that is 43 so square root of 43 so our answer to the question is that the distance between these two points is given by square root of 43. So this is our answer to the question. I hope that you understood the question and enjoyed the session. Have a good day.