 Hi, and welcome to our session. Let us discuss the following question. The question says, find the value of p for which the points minus 5, 1, 1, p, and 4, minus 2 are collinear. We have learned that points a, b, and c collinear area of triangle a, b, c is equal to 0. Equal to minus 5 is equal to 1, and x3 is equal to 4, and is equal to 1, y2 is equal to p, and y3 is equal to minus 2. The area of triangle a, b, c is given by 1 into x2 minus x3 plus y2 into x3 minus x1. Substitute the values of y1, y2, y3, x1, x2, and x3. So, this is equal to 1 by 2 minus 2 into minus 6. This is equal to 1 by 2 into minus 3 plus 3 collinear equals to 1 by 2 into 3 to 0, and this implies p is equal to minus 3. Hence, I require the value of p is minus 3. So, this completes this section by intake care.