 Hi friends, I am Purva and today we will work out the following question, find the equation of the plane with intercept 3 on the y-axis and parallel to z-ox plane. Let A, B and C, B the intercepts on x-axis, y-axis and z-axis respectively. And the equation of the plane is given by x-upon A plus y-upon B plus z-upon C is equal to 1. So this is the key idea behind our question. Let us begin with the solution now. Now we are given that plane is parallel to z-ox plane. It means that it cuts no intercept on either x-axis or z-axis. Now let A, B and C, B the three intercepts on x-axis, y-axis and z-axis respectively. Then we have A is equal to 0, B is equal to 3 and C is equal to 0. Now since the plane cuts no intercept on either x-axis or z-axis, so we have A is equal to 0 and C is equal to 0. Also in the question we are given that the plane cuts intercept 3 on y-axis, so we have B is equal to 3. Now by key idea we know that the equation of the plane is given by x-upon A plus y-upon B plus z-upon C is equal to 1. We mark this as equation 1. Now putting the values of A, B and C in equation 1 we get x-upon 0 plus y-upon 3 plus z-upon 0 is equal to 1 and this implies y-upon 3 is equal to 1 or we get y is equal to 3 is the equation of the plane thus we have got our answer as y is equal to 3. Hope you have understood the solution, bye and take care.