 Hello and welcome to this session. Let us understand the following problem today. Solve the following pair of linear equations. 152x-378y is equal to minus 74 and minus 378x plus 152y is equal to minus 604. Now let us write the solution. Given equations are 152x-378y is equal to minus 74 which is equation 1 and minus 378x plus 152y is equal to minus 604 which is equation 2. Now adding equations 1 and 2 we get 152x-378x minus 378y plus 152y is equal to minus 74 minus 604. Which implies minus 226x minus 226y is equal to minus 678 which implies taking minus 226 common we get x plus y which is equal to minus 678. Now here minus and minus gets cancelled which implies x plus y is equal to 678 divided by 226. This gets cancelled by 3 so which implies x plus y is equal to 3 is our equation 3. Now subtracting equation 2 from equation 1 we get 152x minus minus of 378x minus 138y minus 152y is equal to minus 74 minus 604. Which implies 152x plus 378x minus 530y is equal to 530 which implies 530x minus 530y is equal to 530. Now taking 530 common so we are left with x minus y is equal to 1 this is our equation 4. Now solving equation 3 and 4 we get that is x plus y is equal to 3 and x minus y is equal to 1. Now adding these two equations this gets cancelled we get 2x is equal to 4 which implies x is equal to 4 divided by 2 which implies x is equal to 2. Now substituting x is equal to 2 in equation 3 we get that is x plus y is equal to 3 which implies 2 plus y is equal to 3. Which implies y is equal to 3 minus 2 which implies y is equal to 1. Therefore x is equal to 2 and y is equal to 1 is our required answer. I hope you understood the problem bye and have a nice day.