 Hello friends, welcome to the session. I am Malka. Let's discuss a given question. A vertical pole of length 6 meter cast a shadow 4 meter long on the ground. And at the same time a tar cast a shadow 28 meter long. Find the height of the tar. Now let's start with the solution. Let A be with a vertical pole with a shadow. We all know from the question that A be that is the vertical pole is 6 meter long and the shadow is 4 meter long. Now let D E be the vertical D F be its shadow. We are given in the question that the length of the shadow of tar is 28 meter. We are given that A be that is the length of the pole is 6 meter AC which is the shadow of the vertical pole is 4 meter and D F that is the shadow of the tar is 28 meter. Now let's see in triangle B C and triangle D A is equal to angle D equal to 90 degree C equal to angle F. Because each is the angular elevation of the angle C equal to angle each is the angular elevation of the sun. Now therefore by A A criteria clarity triangle A B C is similar to triangle D E. Now we all know that if two triangles are equal then the ratio of the corresponding sides are equal. So we can say that this implies A B upon D E equal to AC upon D F. This implies on substituting the value of A B AC D E and D F we get A B is 6 and since we have to calculate D E so let this be X equal to AC AC is 4 and D F is 28. This implies now on cross multiplying we get 6 into 28 equal to 4X. This implies X equal to 6 into 28 upon 4. Now on further canceling we get 4 sevens are 28. This implies X equal to 42 meters. Therefore we can say that the height of the tar 42 meters. If you understood the solution and enjoyed the session goodbye and take care.