 Hello and welcome to the session. In this session we will discuss the construction of regular hexagon. Now we know that a hexagon has 6 sides and in a regular hexagon all the sides are equal and all the angles are also equal. So in a regular hexagon the angle will be 3 degrees upon the number of sides of the regular hexagon which is 6 and this would be equal to 16 degrees. So if you look at this regular hexagon a, b, c, d, e, f then these angles you can see we have 6 triangles formed in this regular hexagon. The regular hexagon the area of the equilateral triangle of an equilateral triangle a, b would be given by root 3 by 4 into psi a, b for this. So a, b square, 3, 4, a, b square is the area of the regular hexagon a, b, c, d, e, f. Now we will see we have a property with the radius of the circle d of measure 4 centimeters the regular hexagon on this line a, b. The regular hexagon will be equal to the drawn these two arcs taking a and b are the centers and radius equal to a, b which is of 4 centimeters. And let this point of intersection of the two arcs be point o. The area same as a, b we have drawn these two arcs taking the previous arcs at the point between c and s as the centers and radius equal to 4 centimeters such that these two arcs. Now next hexagon of psi 4 centimeters. Regular hexagon centimeters. Pocketing it says that the length the radius struck the regular hexagon of psi 4 centimeters. The length of the side of the regular hexagon is 4 centimeters. And we know that the length of the side of a regular hexagon is equal to the radius of the circle circle radius 4 centimeters. Now in the next circumference of the circle then in the next torque taking a as the center and radius equal to 4 centimeters. At circumference of the circle at the points d and at this point p the circle where the centers and radius equal to the circle at the point center. So with c or e the radius equal to 4 centimeters such that this arc intersects the center is equal to 4 centimeters. Regular hexagon. Pocketing it says that the length of the side of a regular hexagon is equal to the radius of the circle circle. We have drawn at the use in the construction of a regular circle of measure 4 centimeters and is of measure 120 degrees. So this means angle a and angle b each would be of measure 120 degrees and its opposite sides would be parallel to each other. Measure 4 centimeters the interior angles are of measure 120 degrees that is if angle a and angle b are of measure 120 degrees. Measure 120 degrees d y is of measure 120 degrees. Such that angle b a x is of measure 120 degrees point b such that angle a d y is of measure 120 degrees. Regular hexagon that we have to construct so each side would be of measure 4 centimeters. So we have measure 4 centimeters and b c would also be of measure 4 centimeters. C b also of 4 centimeters, d e of 4 centimeters and e f also of equal to 4 centimeters. A b y third and radius 4 centimeters and this arc intersects the radius b y equal to b c and a b would be parallel to b e to b c. Hence d and e 5 centimeters and d which we have located by taking c f c center and radius 4 centimeters. Now we locate the point e c d e f which each side equal to 4 centimeters.