 Hello and welcome to the session. In this session we discussed the following question which says, draw angle PQR equal to 120 degrees, map two points A and B on the arms PQ and QR respectively. Through A and B drop a pendiculus to the two arms of the angle, let them meet at O is OA equal to OB. Let's see the solution now. First of all we will draw angle PQR equal to 120 degrees. This is angle PQR measuring 120 degrees. Now next we mark two points A and B on the arms PQ and QR respectively. So we have the points A and B on the arms PQ and QR respectively. Next through the points A and B we will draw a pendiculus to the arms PQ and QR to draw the perpendicular at point A on the arm PQ. With A as the center we draw a semicircle of any radius such that the semicircle intersects the arm PQ at points A dash and B dash. Now with A dash as the center and radius more than AA dash we will draw an arc. So we have drawn this arc. Now again with the center B dash and the same radius we draw another arc. So we have drawn this arc intersecting the semicircle at T and the previous arc intersects the semicircle at point C. Now taking C as the center and the radius same as before we draw an arc in the same way taking D as the center and radius same as before we draw another arc intersecting the previous arc. So we have drawn these two arcs intersecting at point say S. Now we join AS so we get this AS perpendicular to the arm PQ. Now in the same way we will draw a perpendicular at point B on the arm QR. So we have drawn this PB perpendicular to QR. Let this point of intersection of the two perpendicular drawn to the arms PQ and QR meet at point O. Now on measuring OA and OB we get OA is equal to OB. So we have drawn an angle PQR of measure 120 degrees. We have taken two points A and B on the arms PQ and QR respectively of the angle PQR. And we have drawn the perpendiculars OA perpendicular to PQ and OB perpendicular to QR. And on measuring OA and OB we get OA is equal to OB. This completes the session. Hope you have understood the solution of this question.