 Hello and welcome to the session. The given question says, construct a triangle ABC in which BC is equal to 4 centimeters and A is 50 degrees and altitude to A is 3 centimeters. Also write the steps of construction. So this construction we shall be doing with the help of construction 11.6 of your book. But just to construct a triangle with given piece vertical angle and altitude to the vertex. Let's write the steps of construction and side by side let us construct the triangle also. So the first step is a line segment BC 4 centimeters. So this is the required line segment BC of length 4 centimeters. Now the second step is that on one side of BC we will do the required angle which is 50 degrees. So here we have drawn angle CBX which measures 50 degrees. Now the third step is angle YBX is equal to 90 degrees. So here we have to draw perpendicular on the line BX. So this is the required perpendicular on the line BX so angle YBX measures 90 degrees. Now the next step is the perpendicular bisector MN of line segment BC YB of line segment BC. And it is the perpendicular bisector of line segment BC such that it intersects the way BY at a point O. Now the first step is draw a circle. So here let us draw a circle with OBS radius. So this is the required circle. Next step is anchor point on MN such that PD is equal to 3 centimeters. Now the seventh step to BC where a line AA dash which is parallel to BC such that the point of intersection of this line with the circle are A and A dash. The next step is A dash B A dash C. And thus we have two triangles ABC and A dash BC such that base of each triangle is 4 centimeters. Altitude AH is equal to 3 centimeters and the angle that is angle A is 50 degrees. Right? Hence the answer is triangle ABC triangle A dash BC are the required triangles. This completes the session. Hope you understood it. Bye and take care.