 and welcome to the session. I am Deepika here. This is a question which says, if the middle of the distribution given below is 28.5, find the values of x and y. Now for the class interval 0 to 10 the frequency is 5, for 10 to 20 it is x, for 20 to 30 it is 20, for 30 to 40 it is 15, for 40 to 50 it is y and for 50 to 60 it is 5, frequencies is 60. Here is a measure of central tendency which gives a value of the middle most observation in the data. Good data. We will not be able to find the middle observation by looking at the cumulative frequencies as a middle observation will be some value a class interval. It is therefore necessary to find the value inside a class that divides the whole distribution into two halves. But the frequencies as close to relative frequency is greater than n by 2 and this is called the medium class. After finding the medium class observations, the frequency of class so this is the key idea behind our cool idea to solve the above question. So let's start the solution 30, 20, 30 to 40 distribution it slides in the class is a low limit of the medium class is 20. The frequency sitting the medium class is equal to 10 which is the class size. We get Cf which is 5 plus x upon 28.5 is equal to 20 minus 5 is 25 minus x upon this implies x is equal to because 28.5 into 2 is 50 plus now x 5 plus 8 is 50 y is equal to sub above question is I hope the solution is clear to you by