 Hi and how are you all today? My name is Priyanka and the question says, in a triangle locate a point in the interior which is equidistant from all its sides in the of the triangle. Now before proceeding on we should know that the point of concurrency of the angle by sector, so here in this question we will be making the angle by sectors of the triangle is called the in-center, right? And that will be, it will be equidistant from all sides and this is our key idea of the question. Let us quickly proceed on with our steps of construction. The first step is to draw a triangle A, B, C. Let us draw a triangle A, B, C. Now the second step is to construct the bisectors of angle B and angle. Now if you remember you know how to draw the angle bisectors of angle B first with the help of compass measure this distance, the equal distance from this as the point draw two arcs and from here again and then join these arcs with B and C respectively and similarly. This is our trigram which I am making to make your understanding clearer and let them intersect at point I and therefore this I, B and I, C are the respective bisector. Now this point I is equidistant from all, if you measure it, it will be equal and it will be the perpendicular distance that you will be measuring. So it will be equidistant from all the sides and on measurement you will find that I, D is equal to I, E is equal to I, F. I am again stressing on this point that I am making this just a rough figure. To make your understanding of this question more clear you will be making in your copies with the help of a scale and a compass you will be getting the exact figure. So this I point lastly, point I equidistant and hope you enjoyed it. Bye for now. Take care.