 Hello and welcome to the session. In this session we will discuss the following question and the question says, construct a triangle ABC with one of its equal sides BC is equal to 6.5 centimeters and vertical angle B is equal to 60 degrees. Let's start the solution now. We are given in the question that one of the equal sides BC is equal to 6.5 centimeters and the vertical angle which is angle B is equal to 60 degrees. So triangle ABC is an isosceles triangle. So we can say that triangle ABC is an isosceles triangle and angle B which is equal to 60 degrees is the vertical angle. Therefore sides AB and BC are equal. This implies AB is equal to BC which is equal to 6.5 centimeters as given in the question. So we have to construct a triangle ABC in which AB is equal to BC which is equal to 6.5 centimeters and angle B is equal to 60 degrees. We will now write down the steps of construction. Step one of construction is draw a line segment BC which is equal to 6.5 centimeters. So we have drawn a line segment BC which is equal to 6.5 centimeters. Step two is at B draw an angle angle PBC equal to 60 degrees. So we will construct an angle PBC at B which is equal to 60 degrees. This is the angle PBC which measures 60 degrees. Step three is with BS center and radius equal to 6.5 centimeters draw an arc to cut BP at A. So with BS center we draw an arc of length 6.5 centimeters and this arc cuts BP at the point A. Step four is join AC. So we join the points A and C. So we have constructed triangle ABC in which AB is equal to BC which is equal to 6.5 centimeters and angle B is equal to 60 degrees. Therefore triangle ABC is the required triangle. With this we end our session. Hope you enjoyed the session.