 Hi, and welcome to the session, I am Deepika here. Let's discuss the question which says, compute the magnitude of the following vectors, factor a is equal to i plus j plus k, factor b is equal to 2i minus 7j minus 3k and factor c is equal to 1 over root 3i plus 1 over root 3j minus 1 over root 3k. Now we know that the length of any vector r given by xi plus yj plus zk is given by, that is, magnitude of vector r is equal to magnitude of xi plus yj plus zk and this is the key idea behind that question. We will take the help of this key idea to solve the above question. So let's start the solution. Now vector a is given by i plus j plus k, therefore according to our key idea, magnitude of vector a is equal to under root of 1 square plus 1 square plus 1 square, that is 1 plus 1 plus 1, which is equal to under root of 3. Now we have given vector b is equal to 2i minus 7j minus 3k, therefore according to our key idea, magnitude of vector b is equal to under root of 2 square plus minus 7 square plus minus 3 square, that is 2 plus 49 plus 9 and this is equal to under root of 6j2. Again, vector c is given to us 1 over root 3i plus 1 over root 3j minus 1 over root 3k, therefore magnitude of vector c is equal to under root of 1 over root 3 square plus 1 over root 3 square plus 1 over root 3 square, that is 1 over 3 plus 1 over 3 plus 1 over 3 and this is equal to under root of 3 over 3, which is equal to 1. Hence the answer for this question is, magnitude of vector a is equal to root 3, magnitude of vector b is equal to under root of 6j2 and magnitude of vector c is equal to 1. Now I hope the solution is clear to you and you have enjoyed the session. Bye and have a nice day.